Question

我的Spring Web应用程序与JPA和Glassfish服务器有问题。当我尝试向数据库添加新条目（entityManager.persist()）时，我收到：

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.transaction.CannotCreateTransactionException: Could not open JPA EntityManager for transaction; nested exception is java.lang.IllegalStateException: A JTA EntityManager cannot use getTransaction()

这是我的代码：

的persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence">
  <persistence-unit name="LibraryPU">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <jta-data-source>jdbc/sample</jta-data-source>
    <properties>
      <property name="hibernate.transaction.jta.platform" value="org.hibernate.service.jta.platform.internal.SunOneJtaPlatform"/>
      <property name="hibernate.show_sql" value="true" />
    </properties>
  </persistence-unit>
</persistence>

调度-servlet.xml中

<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:aop="http://www.springframework.org/schema/aop"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
       http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
       http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
       http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>


    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/WEB-INF/jsp/"
          p:suffix=".jsp" />


    <context:component-scan base-package="service, controller, dao" />


    <bean id="entityManagerFactory"
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="persistenceXmlLocation" value="classpath:META-INF/persistence.xml" />
        <property name="persistenceUnitName" value="LibraryPU" />
        <property name="dataSource" ref="dataSource" />
        <property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
        <property name="jpaDialect" ref="jpaDialect" />
    </bean>
    <bean id="jpaVendorAdapter"
          class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
        <property name="database" value="HSQL" />
        <property name="databasePlatform" value="org.hibernate.dialect.HSQLDialect" />
    </bean>

    <bean id="jpaDialect" class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />

    <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="org.apache.derby.jdbc.ClientDriver" />
        <property name="url" value="jdbc:derby://localhost:1527/Library" />
        <property name="username" value="app" />
        <property name="password" value="app" />
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>
    <tx:annotation-driven transaction-manager="transactionManager"/>

</beans>

UserDao.java

package dao;

import entity.User;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.NoResultException;
import javax.persistence.PersistenceContext;
import javax.persistence.Query;

import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;


@Repository("userDao")
@Transactional
public class UserDao {
    @PersistenceContext
    private EntityManager entityManager;

    @Transactional
    public void insert(User user) {
        entityManager.persist(user);
        entityManager.flush();
    }
}

提前致谢！

Answer 1

如果您想在代码中使用JTA事务，那么

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">

删除JpaTransactionManager并将其替换为JTA事务管理器。

同时定义transacation-type="JTA"喜欢

<persistence-unit name="LibraryPU" transaction-type="JTA">

persistence.xml中的

。

Spring JPA错误：JTA EntityManager无法使用getTransaction（）

1 个答案: