我在使用这个程序时遇到了一些麻烦。 几乎我需要从一个包含名字和姓名,cookie类型,购买金额,成本以及是否付款的文件中读取。
我相信我的功能是正确的。
当我运行程序时,它运行正常,但在某些数字之间看起来是额外的数字。我的意思是,如果输入文件是: 约翰格林薄荷1 1.00 Y. Jane Blue筹码2 2.00 N. 输出文件将类似于: John Green 12 20000 mint 455 1等...
有什么想法吗?我猜我在阅读文件/将它们存储到结构中时搞砸了。
#include <stdio.h>
#include <ctype.h>
/*structure definition*/
struct customer{
char first[12], last[12], type[10], paid;
int boxes;
float cost;
};
/*prototypes*/
void readCustomerData(FILE*, struct customer[]);
void printCustomerData(FILE*, int, struct customer[]);
float moneyReceived(int, struct customer[]);
int custWhoOwe(int, struct customer[]);
float moneyOutstanding(int, struct customer[]);
int moneyReceivedPercent(int, struct customer[]);
int main (){
int numCustomers;
float money, money2;
int cust, perc;
FILE*input;
FILE*output;
input = fopen("custInfo.txt", "r");
output = fopen("output.txt", "w");
fscanf(input, "%d", &numCustomers);
struct customer customerData[numCustomers];
readCustomerData(input, customerData);
printCustomerData(output, numCustomers, customerData);
fprintf(output, "Summary:\n\n");
money = moneyReceived(numCustomers, customerData);
fprintf(output, "Total Cash Received: $%.2f\n\n", money);
cust = custWhoOwe(numCustomers, customerData);
fprintf(output, "Num customers who have not paid: %d\n\n", cust);
money2 = moneyOutstanding(numCustomers, customerData);
fprintf(output, "Total Amount Outstanding: $%.2f\n\n", money2);
perc = moneyReceivedPercent(numCustomers, customerData);
fprintf(output, "Percentage of Sales outstanding: %d%%\n\n", perc);
fclose(input);
fclose(output);
return 0;
}
void readCustomerData(FILE*file, struct customer cdata[]){
int numCustomers, i;
file = fopen("custInfo.txt", "r");
fscanf(file, "%d", &numCustomers);
for (i=0; i<numCustomers; i++){
fscanf(file, "%s%s%s%d%f%c", &cdata[i].first, &cdata[i].last, &cdata[i].type, &cdata[i].boxes, &cdata[i].cost, &cdata[i].paid);
}
fclose(file);
}
void printCustomerData(FILE*file, int num, struct customer cdata[]){
int i;
fprintf(file, "Customers:\n\n");
fprintf(file, "Name\t\tType of Cookie\t\tNum of Boxes\tCost of Box\tPaid\n");
fprintf(file, "--------------------------------------------------------------------------------\n\n");
for (i=0; i<num; i++){
fprintf(file, "%s %s\t", cdata[i].first, cdata[i].last);
fprintf(file, "%s\t\t", cdata[i].type);
fprintf(file, "%d\t\t", cdata[i].boxes);
fprintf(file, "$%.2f\t\t", cdata[i].cost);
fprintf(file, "%c", cdata[i].paid);
fprintf(file, "\n\n");
}
fprintf(file, "\n\n\n\n\n");
}
float moneyReceived(int num, struct customer cdata[]){
int i, sum=0;
for (i=0; i<num; i++){
if(cdata[i].paid=='Y'){
sum= sum+(cdata[i].cost*cdata[i].boxes);}
}
return sum;
}
int custWhoOwe(int num, struct customer cdata[]){
int count=0, i;
for (i=0; i<num; i++){
if (cdata[i].paid=='N'){
count++;}
}
return count;
}
float moneyOutstanding(int num, struct customer cdata[]){
int i, sum=0;
for (i=0; i<num; i++){
if (cdata[i].paid=='N'){
sum= sum+(cdata[i].cost*cdata[i].boxes);}
}
return sum;
}
int moneyReceivedPercent(int num, struct customer cdata[]){
int answ;
float money, moneyOut;
money = moneyReceived(num, cdata);
moneyOut = moneyOutstanding(num, cdata);
answ=(moneyOut/money)*100;
return answ;
}
答案 0 :(得分:1)
除非规范包含
[
,c
或n
说明符,否则将跳过输入空白字符(由isspace函数指定)。 C11§7.21.6.28
1)在"%c"
之前添加空格以消耗空白。 "%c"
本身不会这样做。即使没有前导空格,其他使用的说明符也会这样做。
2)检查*scanf()
函数的返回值。除非返回值为6,否则在这种情况下,不要相信扫描成功完成。
3)通过声明宽度小于'%s'
的大小来限制字符串输入。当然应该防止代码超出阵列。
for (i=0; i<numCustomers; i++){
// fscanf(file, "%s%s%s%d%f%c", &cdata[i].first, &cdata[i].last,
// &cdata[i].type, &cdata[i].boxes, &cdata[i].cost, &cdata[i].paid);
if (6 != fscanf(file, "%11s%11s%9s%d%f %c",
&cdata[i].first, &cdata[i].last, &cdata[i].type,
&cdata[i].boxes, &cdata[i].cost, &cdata[i].paid)) {
printf("Bad input!");
}
}