Question

问题很简单。我有一个数组，比如

let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10],
    maxChunkLength = 3;

我需要将它拆分为多个数组，以获得：

[[1, 2, 3], [3, 4, 5], [5, 6, 7], [7, 8, 9], [9, 10]]

请注意，块的最后一个元素应该是它旁边的块的第一个元素。

有人知道最好的方法吗？

Answer 1

此功能可能适合您，

function splitArray(array, chunk){      
    var i,j, rslt = [];
    chunk = chunk - 1;
    for (i=0,j=array.length; i<j; i+=chunk) {
        rslt.push(array.slice(i,i+chunk +1));
    }
    return rslt;
}

实施例

splitArray([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 3); //[[1, 2, 3], [3, 4, 5], [5, 6, 7], [7, 8, 9], [9, 10]]

Answer 2

这大约是接受答案的两倍。

function chunk(arr, chunkSize) {
    var curr = [], result = [], i, j;

    for (i=0, j=arr.length; i<j; i++) {
        curr.push(arr[i]);        
        if (curr.length === chunkSize) {
            result.push(curr);
            curr = [arr[i]];
        }
    }    

    if (curr.length !== chunkSize) {     
        result.push(curr);
    }
    
    return result;
}

document.write(JSON.stringify(chunk([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 3)));

Answer 3

这对你有用吗？

var originalArray = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

var maxChunkLength = 3

var newArray = [];

for (var i = 0; i < originalArray.length; maxChunkLength += 2) {

    var tempArray = [];

    for (var j = i; j < i+maxChunkLength; j++) {

        if (typeof originalArray[j] !== "undefined") {

            tempArray.push(originalArray[j]);
        } 
    }

newArray.push(tempArray);

tempArray = [];  
}

Answer 4

这应该有效，

var arr = [1,2,3,4,5,6,7,8];
var el1 = 0, el2 = 0, el3 = 0;
var result = [];
var splitLength = 3;
for(var i = 0; i < arr.length; i += (splitLength -1) ) {
    var tempArr = [];
    for(var j = 0; j < splitLength && arr[i+j]; j++) {
        tempArr.push(arr[i+j]);
    }

    result.push(tempArr);
}

console.log("[" + result.join("]\n[") + "]");

以块为单位拆分数组

4 个答案: