Question

ProjID  Dno RNo Status       DateApproved
  100   1   1   Initiated   2014-12-31 09:15:58.000
  100   1   1   Approved    2015-01-31 09:15:58.000
  100   1   1   Approved    2015-02-01 09:15:58.000
  100   1   1   Approved    2015-05-28 09:15:58.000
  100   1   1   Approved    2015-06-20 09:15:58.000
  101   1   1   Approved    2014-12-31 09:15:58.000
  101   1   1   Approved    2015-01-31 09:15:58.000
  101   1   1   Approved    2015-02-01 09:15:58.000
  101   1   1   Approved    2015-05-28 09:15:58.000
  101   1   1   Approved    2015-08-20 09:15:58.000

在上面的示例中，我必须为每个项目获得最多（Dateapproved）作为Dateapproved。如果所有修订状态都在特定组中被批准，例如：项目ID = 101，其组中的所有行都具有已批准的状态，因此我必须获得最大日期：＆＃39; 2015-08-20 09:15 ：58.000＆＃39;。但是对于Projectid = 100，一个状态仍处于启动状态，因此我们必须将Null显示为Dateapproved。

先谢谢

我的输出应该是：

ProjId Dno Rno DateApproved
100      1  1   NUll
101      1  1   2015-08-20 09:15:58.000

示例代码：

Create table #temp(
ProjectID varchar(35),
Documentno int,
Revisionno int,
Status varchar(35),
DateApproved Datetime)

insert into #temp values ( '100',    1,  1,  'Initiated','2014-12-31 09:15:58')
insert into #temp values ( '100',    1,  1,  'Approved','2015-01-31 09:15:58 ')
insert into #temp values ( '100',    1,  1,  'Approved','2015-02-01 09:15:58 ')
insert into #temp values ( '100',    1,  1,  'Approved','2015-05-28 09:15:58 ')
insert into #temp values ( '100',    1,  1,  'Approved','2015-06-20 09:15:58 ')


insert into #temp values ( '101',    1,  1,  'Approved','2014-12-31 09:15:58 ')
insert into #temp values ( '101',    1,  1,  'Approved','2015-01-31 09:15:58 ')
insert into #temp values ( '101',    1,  1,  'Approved','2015-02-01 09:15:58 ')
insert into #temp values ( '101',    1,  1,  'Approved','2015-05-28 09:15:58 ')
insert into #temp values ( '101',    1,  1,  'Approved','2015-08-20 09:15:58 ')


select * from #temp

Answer 1

试试这个：

SELECT T.ProjectID,
       Documentno as Dno, 
       Revisionno  as RNo,
       CASE WHEN SUM(CASE WHEN T.Status <> 'Approved' THEN 1 ELSE 0 END) = 0 
            THEN Max(T.DateApproved) ELSE NULL
       END as DateApproved 
from #temp T
GROUP BY T.ProjectId, Documentno , Revisionno

在针对您的测试数据运行时，它会提供以下输出：

PROJECT ID  DNo    TNo   DateApproved
100         1      1      NULL
101         1      1      2015-08-20 09:15:58.000

Answer 2

您可以使用case语句和条件聚合执行此操作。使用Approved获取非COUNT(NULLIF(Status, 'Approved'))的状态计数。如果这是0，那么获得批准的最大日期：

SELECT  ProjectID,
        DateApproved = CASE WHEN COUNT(NULLIF(Status, 'Approved')) = 0 THEN MAX(DateApproved) END
FROM    #Temp
GROUP BY ProjectID;

根据条件

2 个答案: