这是我的问题: 为了简化我使用IntentService使用Messenger对象处理一对消息,第一条消息(msg.what == 1)启动10秒进程,第二条消息(msg.what == 2)启动5秒进程。这些消息由绑定到我的服务的第三方活动发送,并且正在等待对这些已发送消息的回复。
一切正常但如果消息1正在运行,则在发送消息2时,它将等待第一个进程完成处理。当我读到这个Intent Service的预期行为时(消息在外部线程中按顺序排队和处理)。
但是当前一个消息仍在运行时,有没有一个技巧可以对新发送的消息进行异步响应?(即当消息1仍在运行时获得对消息2的回复)我试过在我的handleMessage函数上使用thread和asynctask没有成功(我甚至没有在活动中得到我的请求的任何答案)
服务类:处理程序
class IncomingHanlder extends Handler {
@Override
public void handleMessage(Message msg) {
try {
switch (msg.what) {
case 1:
//Process taking 10 sec
//...
//Reply to client
Message resp = Message.obtain(null, msg.what);
Bundle bResp = new Bundle();
bResp.putBoolean("com.xxx.msg1", true);
resp.setData(bResp);
msg.replyTo.send(resp);
break;
case 2:
//Process taking 5 sec
//...
//Reply to client
Message resp = Message.obtain(null, msg.what);
Bundle bResp = new Bundle();
bResp.putBoolean("com.xxx.msg2", true);
resp.setData(bResp);
msg.replyTo.send(resp);
break;
default:
super.handleMessage(msg);
}
}
catch (RemoteException e) {
e.printStackTrace();
}
}
}
private Messenger msg = new Messenger(new IncomingHanlder ());
@Override
public IBinder onBind(Intent arg0) {return msg.getBinder();}
客户类:活动(第三方应用程序)
ServiceConnection sConn = new ServiceConnection() {
@Override
public void onServiceDisconnected(ComponentName name) {
messenger = null;
}
@Override
public void onServiceConnected(ComponentName name, IBinder service) {
// We are connected to the service
messenger = new Messenger(service);
}
};
// We bind to the service
Intent i = new Intent("com.xxx.myserviceboundpackage");
try {
//If service is always launched
stopService(i);
}
catch (Exception e){}
//Bind to service
bindService(i, sConn,
Context.BIND_AUTO_CREATE);
在客户端:点击按钮发送消息(例如消息1)
try {
Message msg = Message
.obtain(null, 1);
msg.replyTo = new Messenger(new ResponseHandler());;
try {
messenger.send(msg);
} catch (RemoteException e) {
}
}
catch (Exception e)
{
e.printstacktrace();
}
在客户端:处理来自服务回复的消息
class ResponseHanlder extends Handler {
@Override
public void handleMessage(Message msg) {
try {
switch (msg.what) {
//Response to each request
case 1:
//Process which have taken 10 sec
Bundle bundle = msg.getData();
Boolean myResp = bundle.getBoolean("com.xxx.msg1");
if (myResp) {//do something}
break;
case 2:
//Process which have taken 5 sec
Bundle bundle = msg.getData();
Boolean myResp = bundle.getBoolean("com.xxx.msg2");
if (myResp) {//do something}
break;
default:
super.handleMessage(msg);
}
}
catch (RemoteException e) {
e.printStackTrace();
}
}
}
感谢您的建议。
答案 0 :(得分:0)
好的,考虑到pskink的链接(http://pastebin.com/L1m3NJTT)
这是我尝试过的:我现在扩展了Service而不再使用IntentService。我的处理程序现在是
class IncomingHanlder extends Handler {
@Override
public void handleMessage(Message msg) {
pool.submit(new MyRunnable(msg));
super.handleMessage(msg);
}
}
此方法必须在myRunnable方法中使用replyto方法获取传入消息(msg)
public class MyRunnable implements Runnable {
private final Message _message;
public MyRunnable(final Message message) {
this._message = message;
}
@Override
public void run() {
try {
switch (this._message.what) {
case 1:
//Process taking 10 sec
//...
//Reply to client
Message resp = Message.obtain(null, this._message.what);
Bundle bResp = new Bundle();
bResp.putBoolean("com.xxx.msg1", true);
resp.setData(bResp);
this._message.replyTo.send(resp);
break;
case 2:
//Process taking 5 sec
//...
//Reply to client
Message resp = Message.obtain(null, this._message.what);
Bundle bResp = new Bundle();
bResp.putBoolean("com.xxx.msg2", true);
resp.setData(bResp);
this._message.replyTo.send(resp);
break;
default:
}
}
catch (RemoteException e) {
e.printStackTrace();
}
}
}
请注意,我仍然使用Service Interface onBind实现:
private Messenger msg = new Messenger(new ConvertHanlder());
@Override
public IBinder onBind(Intent arg0) {
return msg.getBinder();
}
事实是:我现在从未在发送消息的活动中得到任何答案。我错过了什么吗?