Question

我想使用

android.permission.CAMERA
android.permission.WRITE_EXTERNAL_STORAGE

ActivityCompat.requestPermissions(Activity activity,new String permisionList[],int permissionRequestcode);

但我的问题是我只要求一次许可，我读到了关于组权限的内容，但它只适用于由开发人员决定的同一组，如CONTACT_GROUP : read_contact,write_contact等。

我想创建自定义组权限，只向我询问一个请求＆amp;只给我一个答复。

由于

Answer 1

您可以在单个请求中询问多个权限（来自不同的群组）。为此，您需要将您提供的字符串数组的所有权限作为requestPermissions API的第一个参数添加，如下所示：

requestPermissions(new String[]{
                                Manifest.permission.READ_CONTACTS,
                                Manifest.permission.ACCESS_FINE_LOCATION},
                        ASK_MULTIPLE_PERMISSION_REQUEST_CODE);

执行此操作时，您将看到权限弹出窗口是多个权限弹出窗口的堆栈。当然，您需要处理每个权限的接受和拒绝（包括＆＃34; Never Ask Again＆＃34;）选项。在here上已经很好地解释了这一点。

Answer 2

首先初始化权限请求代码

public  static final int PERMISSIONS_MULTIPLE_REQUEST = 123;

检查android版本

 private void checkAndroidVersion() {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
        checkPermission();

    } else {
        // write your logic here
    }

}

检查多个权限代码

 private void checkPermission() {
    if (ContextCompat.checkSelfPermission(getActivity(),
            Manifest.permission.READ_EXTERNAL_STORAGE) + ContextCompat
            .checkSelfPermission(getActivity(),
                    Manifest.permission.CAMERA)
            != PackageManager.PERMISSION_GRANTED) {

        if (ActivityCompat.shouldShowRequestPermissionRationale
                (getActivity(), Manifest.permission.READ_EXTERNAL_STORAGE) ||
                ActivityCompat.shouldShowRequestPermissionRationale
                        (getActivity(), Manifest.permission.CAMERA)) {

      Snackbar.make(getActivity().findViewById(android.R.id.content),
                    "Please Grant Permissions to upload profile photo",
                    Snackbar.LENGTH_INDEFINITE).setAction("ENABLE",
                    new View.OnClickListener() {
                        @Override
                        public void onClick(View v) {
                            requestPermissions(
                                    new String[]{Manifest.permission
                                            .READ_EXTERNAL_STORAGE, Manifest.permission.CAMERA},
                                    PERMISSIONS_MULTIPLE_REQUEST);
                        }
                    }).show();
        } else {
            requestPermissions(
                    new String[]{Manifest.permission
                            .READ_EXTERNAL_STORAGE, Manifest.permission.CAMERA},
                    PERMISSIONS_MULTIPLE_REQUEST);
        }
    } else {
        // write your logic code if permission already granted
    }
}

用户授予许可后回拨方法

@Override
public void onRequestPermissionsResult(int requestCode,
                                       @NonNull String[] permissions, @NonNull int[] grantResults) {

    switch (requestCode) {
        case PERMISSIONS_MULTIPLE_REQUEST:
            if (grantResults.length > 0) {
               boolean cameraPermission = grantResults[1] == PackageManager.PERMISSION_GRANTED;
               boolean readExternalFile = grantResults[0] == PackageManager.PERMISSION_GRANTED;

                if(cameraPermission && readExternalFile)
                {
                    // write your logic here 
                } else {
                    Snackbar.make(getActivity().findViewById(android.R.id.content),
                        "Please Grant Permissions to upload profile photo",
                        Snackbar.LENGTH_INDEFINITE).setAction("ENABLE",
                        new View.OnClickListener() {
                            @Override
                            public void onClick(View v) {
                                requestPermissions(
                                        new String[]{Manifest.permission
                                                .READ_EXTERNAL_STORAGE, Manifest.permission.CAMERA},
                                        PERMISSIONS_MULTIPLE_REQUEST);
                            }
                        }).show();
                }
           }
           break;
    }
}

Answer 3

在此阶段没有黑客可以绕过要求不同组的权限。这就是android如何开发运行时权限的本质，让用户可以选择接受哪些权限。当然不接受应用程序所需的所有权限，可能会使应用程序无法正常工作。

CAMERA和WRITE_EXTERNAL_STORAGE都是regarded as dangerous permissions，并且在不同的组中，因此都需要runtime permission request.

一旦为特定组授予了权限，就不需要在应用程序运行的生命周期内再次请求权限，或者如果以默认设置的形式将其撤消，则不需要再次请求权限。

您唯一能做的就是要求用户接受默认决策，可以撤销，by using "never ask again"

Answer 4

我遇到了同样的问题，偶然发现了library。

基本上，您可以按顺序请求多个权限，如果用户拒绝您的许可，您可以添加侦听器以弹出快餐栏。

Answer 5

如前所述，目前每个权限组都有自己的权限对话框，必须单独调用。

每个权限组都有不同的对话框，但您可以在onRequestPermissionsResult（）回调方法中一起检查结果。

Here is a working example link, may be useful for someone.

Answer 6

我遇到了同样的问题，下面是我提出的解决方法：

public boolean checkForPermission(final String[] permissions, final int permRequestCode, int msgResourceId) {
        final List<String> permissionsNeeded = new ArrayList<>();
        for (int i = 0; i < permissions.length; i++) {
            final String perm = permissions[i];
            if (ContextCompat.checkSelfPermission(getActivity(), permissions[i]) != PackageManager.PERMISSION_GRANTED) {
                if (shouldShowRequestPermissionRationale(permissions[i])) {
                    final AlertDialog dialog = AlertDialog.newInstance( getResources().getString(R.string.permission_title), getResources().getString(msgResourceId) );
                    dialog.setPositiveButton("OK", new View.OnClickListener() {
                        @Override
                        public void onClick(View view) {
                            // add the request.
                            permissionsNeeded.add(perm);
                            dialog.dismiss();
                        }
                    });
                    dialog.show( getActivity().getSupportFragmentManager(), "HCFAlertDialog" );
                } else {
                    // add the request.
                    permissionsNeeded.add(perm);
                }
            }
        }

        if (permissionsNeeded.size() > 0) {
            // go ahead and request permissions
            requestPermissions(permissionsNeeded.toArray(new String[permissionsNeeded.size()]), permRequestCode);
            return false;
        } else {
            // no permission need to be asked so all good...we have them all.
            return true;
        }
    }

你可以这样称呼上述方法：

if ( checkForPermission( new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE, 
Manifest.permission.CAMERA}, REQUEST_PERMISSION_EXTERNAL_STORAGE_RESULT, R.string.permission_image) ) {
                        // DO YOUR STUFF

                    }

Answer 7

对于多个权限，您可以使用以下代码：

final private int REQUEST_CODE_ASK_MULTIPLE_PERMISSIONS = 124;

private void insertDummyContactWrapper() {
    List<String> permissionsNeeded = new ArrayList<String>();

    final List<String> permissionsList = new ArrayList<String>();
    if (!addPermission(permissionsList, Manifest.permission.ACCESS_FINE_LOCATION))
        permissionsNeeded.add("GPS");
    if (!addPermission(permissionsList, Manifest.permission.READ_CONTACTS))
        permissionsNeeded.add("Read Contacts");
    if (!addPermission(permissionsList, Manifest.permission.WRITE_CONTACTS))
        permissionsNeeded.add("Write Contacts");

    if (permissionsList.size() > 0) {
        if (permissionsNeeded.size() > 0) {
            // Need Rationale
            String message = "You need to grant access to " + permissionsNeeded.get(0);
            for (int i = 1; i < permissionsNeeded.size(); i++)
                message = message + ", " + permissionsNeeded.get(i);
            showMessageOKCancel(message,
                    new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which) {
                            requestPermissions(permissionsList.toArray(new String[permissionsList.size()]),
                                    REQUEST_CODE_ASK_MULTIPLE_PERMISSIONS);
                        }
                    });
            return;
        }
        requestPermissions(permissionsList.toArray(new String[permissionsList.size()]),
                REQUEST_CODE_ASK_MULTIPLE_PERMISSIONS);
        return;
    }

    insertDummyContact();
}

private boolean addPermission(List<String> permissionsList, String permission) {
    if (checkSelfPermission(permission) != PackageManager.PERMISSION_GRANTED) {
        permissionsList.add(permission);
        // Check for Rationale Option
        if (!shouldShowRequestPermissionRationale(permission))
            return false;
    }
    return true;
}

Answer 8

       // **For multiple permission you can use this code :**

       // **First:**
//Write down in onCreate method.

         if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
                    requestPermissions(new String[]{
                                    android.Manifest.permission.READ_EXTERNAL_STORAGE,
                                    android.Manifest.permission.CAMERA},
                            MY_PERMISSIONS_REQUEST);

         }

        //**Second:**
    //Write down in a activity.
     @Override
        public void onRequestPermissionsResult(int requestCode,
                                               String permissions[], int[] grantResults) {
            switch (requestCode) {
                case MY_PERMISSIONS_REQUEST:

                    if (grantResults.length > 0
                            && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                        new Handler().postDelayed(new Runnable() {
                            @Override
                            public void run() {
                                progressBar.setVisibility(View.GONE);
                                Intent i = new Intent(SplashActivity.this,
                                        HomeActivity.class);
                                startActivity(i);
                                finish();
                            }
                        }, SPLASH_DISPLAY_LENGTH);

                    } else {
                        finish();
                    }
                    return;
            }
        }

Answer 9

根据我搜索的内容，我认为这是我发现的最佳答案Android 6.0 multiple permissions

Answer 10

为不同类型的权限添加通用代码。复制粘贴，稍有更改。阅读＆＃34; TODO＆＃34;以下代码中的评论。

将以下活动设为启动器活动：

public class PermissionReqActivity extends AppCompatActivity {

    private static final int CODE_WRITE_SETTINGS_PERMISSION = 332;
    private static String[] PERMISSIONS_ALL = {Manifest.permission.WRITE_EXTERNAL_STORAGE}; //TODO You can Add multiple permissions here.
    private static final int PERMISSION_REQUEST_CODE = 223;
    private Context context;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_permission_req);
        context = this;

        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {

            boolean allPermissionsGranted = true;
            ArrayList<String> toReqPermissions = new ArrayList<>();

            for (String permission : PERMISSIONS_ALL) {
                if (ActivityCompat.checkSelfPermission(this, permission) != PackageManager.PERMISSION_GRANTED) {
                    toReqPermissions.add(permission);

                    allPermissionsGranted = false;
                }
            }
            if (allPermissionsGranted)
                //TODO Now some permissions are very special and require Settings Activity to launch, as u might have seen in some apps. handleWriteSettingsPermission() is an example for WRITE_SETTINGS permission. If u don't need very special permission(s), replace handleWriteSettingsPermission() with initActivity().
                handleWriteSettingsPermission();
            else
                ActivityCompat.requestPermissions(this,
                        toReqPermissions.toArray(new String[toReqPermissions.size()]), PERMISSION_REQUEST_CODE);
        }
    }

    @Override
    public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
        if (requestCode == PERMISSION_REQUEST_CODE) {
            boolean allPermGranted = true;
            for (int i = 0; i < grantResults.length; i++) {
                if (grantResults[i] != PackageManager.PERMISSION_GRANTED) {
                    Toast.makeText(this, "Permissions not granted: " + permissions[i], Toast.LENGTH_LONG).show();
                    allPermGranted = false;
                    finish();
                    break;
                }
            }
            if (allPermGranted)
                handleWriteSettingsPermission();//TODO As mentioned above, use initActivity() here if u dont need very special permission WRITE_SETTINGS
        }
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
    }

    private void handleWriteSettingsPermission() {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            if (Settings.System.canWrite(context)) {
                initActivity();
            } else {
                Toast.makeText(this, "Please Enable this permission for " +
                        getApplicationInfo().loadLabel(getPackageManager()).toString(), Toast.LENGTH_LONG).show();
                Intent intent = new Intent(Settings.ACTION_MANAGE_WRITE_SETTINGS);
                intent.setData(Uri.parse("package:" + context.getPackageName()));
                startActivityForResult(intent, CODE_WRITE_SETTINGS_PERMISSION);
            }
        }
    }

//TODO You don't need the following onActivityResult() function if u dont need very special permissions.

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M && requestCode == CODE_WRITE_SETTINGS_PERMISSION) {
            if (Settings.System.canWrite(this))
                initActivity();
            else {
                Toast.makeText(this, "Permissions not granted: " + Manifest.permission.WRITE_SETTINGS, Toast.LENGTH_LONG).show();
                finish();
            }
        }
    }

    private void initActivity() {
        startActivity(new Intent(this, MainActivity.class));
    }
}

Answer 11

基于vedval，我有此解决方案。

public boolean checkForPermission(final String[] permissions, final int permRequestCode) {
    if (Build.VERSION.SDK_INT < Build.VERSION_CODES.M) {
        return true;
    }
    final List<String> permissionsNeeded = new ArrayList<>();
    for (int i = 0; i < permissions.length; i++) {
        final String perm = permissions[i];
        if (ContextCompat.checkSelfPermission(this, permissions[i]) != PackageManager.PERMISSION_GRANTED) {
            if (shouldShowRequestPermissionRationale(permissions[i])) {
                Snackbar.make(phrase, R.string.permission_location, Snackbar.LENGTH_INDEFINITE)
                        .setAction(android.R.string.ok, new View.OnClickListener() {
                            @Override
                            @TargetApi(Build.VERSION_CODES.M)
                            public void onClick(View v) {
                                permissionsNeeded.add(perm);
                            }
                        });
            } else {
                // add the request.
                permissionsNeeded.add(perm);
            }
        }
    }

    if (permissionsNeeded.size() > 0) {
        // go ahead and request permissions
        requestPermissions(permissionsNeeded.toArray(new String[permissionsNeeded.size()]), permRequestCode);
        return false;
    } else {
        // no permission need to be asked so all good...we have them all.
        return true;
    }
}

/**
 * Callback received when a permissions request has been completed.
 */
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions,
                                       @NonNull int[] grantResults) {
    if (requestCode == REQUEST_READ_LOCATION) {
        int i = 0;
        for (String permission : permissions ){
            if ( permission.equals(Manifest.permission.ACCESS_FINE_LOCATION) && grantResults.length > 0 && grantResults[i] == PackageManager.PERMISSION_GRANTED) {
                initLocationManager();
            }
            i++;
        }

    }
}

Answer 12

这里我有一个简单的解决方案，-（多次权限检查）

String[] permissions = new String[]{
            Manifest.permission.WRITE_CALL_LOG,
            Manifest.permission.READ_CALL_LOG,
            Manifest.permission.READ_CONTACTS,
            Manifest.permission.WRITE_CONTACTS}; // Here i used multiple permission check

然后在Oncreate中调用它

 if (checkPermissions()) {
            //  permissions  granted.
            getCallDetails();
        }

最后，复制下面的代码

private boolean checkPermissions() {
        int result;
        List<String> listPermissionsNeeded = new ArrayList<>();
        for (String p : permissions) {
            result = ContextCompat.checkSelfPermission(getApplicationContext(), p);
            if (result != PackageManager.PERMISSION_GRANTED) {
                listPermissionsNeeded.add(p);
            }
        }
        if (!listPermissionsNeeded.isEmpty()) {
            ActivityCompat.requestPermissions(this, listPermissionsNeeded.toArray(new String[listPermissionsNeeded.size()]), MULTIPLE_PERMISSIONS);
            return false;
        }
        return true;
    }


    @Override
    public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
        switch (requestCode) {
            case MULTIPLE_PERMISSIONS: {
                if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    // permissions granted.
                    getCallDetails(); // Now you call here what ever you want :)
                } else {
                    String perStr = "";
                    for (String per : permissions) {
                        perStr += "\n" + per;
                    }
                    // permissions list of don't granted permission
                }
                return;
            }
        }
    }

Answer 13

我来晚了，但是我想告诉图书馆我以什么结尾。

RxPermission是具有反应性代码的最佳库，这使得权限代码仅出乎意料地仅占1行。

RxPermissions rxPermissions = new RxPermissions(this);
rxPermissions
.request(Manifest.permission.CAMERA,
         Manifest.permission.READ_PHONE_STATE)
.subscribe(granted -> {
    if (granted) {
       // All requested permissions are granted
    } else {
       // At least one permission is denied
    }
});

添加您的build.gradle

allprojects {
    repositories {
        ...
        maven { url 'https://jitpack.io' }
    }
}

dependencies {
    implementation 'com.github.tbruyelle:rxpermissions:0.10.1'
    implementation 'com.jakewharton.rxbinding2:rxbinding:2.1.1'
}

Answer 14

检查多个权限，如果未授予，则请求

 public void checkPermissions(){
    if(ContextCompat.checkSelfPermission(getApplicationContext(),
            Manifest.permission.WRITE_EXTERNAL_STORAGE)== PackageManager.PERMISSION_GRANTED && ContextCompat.checkSelfPermission(getApplicationContext(),Manifest.permission.CAMERA)==PackageManager.PERMISSION_GRANTED){
        //Do_SOme_Operation();
    }else{
        requestStoragePermission();
    }
}

public void requestStoragePermission(){
    ActivityCompat.requestPermissions(this
            ,new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE,Manifest.permission.CAMERA},1234);
}

@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
    switch (requestCode){
        case 1234:if(grantResults[0]==PackageManager.PERMISSION_GRANTED && grantResults[1]==PackageManager.PERMISSION_GRANTED){
  // Do_SOme_Operation();
        }

        default:super.onRequestPermissionsResult(requestCode,permissions,grantResults);
    }
}

Answer 15

您应该使用名为 dexter 的依赖项，如下所示： https://github.com/Karumi/Dexter 通过这种方式，您可以轻松获得一项或多项许可：这是给定的代码

    Dexter.withContext(this).
               withPermissions(Manifest.permission.CAMERA,
          Manifest.permission.WRITE_EXTERNAL_STORAGE)
               .withListener(new MultiplePermissionsListener() {
                  @Override
                    public void onPermissionsChecked(MultiplePermissionsReport 
                    multiplePermissionsReport) {
                    displaySong();
                  }

                @Override
                public void    onPermissionRationaleShouldBeShown(List<PermissionRequest> list,     
        PermissionToken permissionToken) {

                    permissionToken.continuePermissionRequest();

                }
            }).check();

Answer 16

用于一次请求多个权限，您可以使用此方法link

compile 'com.kishan.askpermission:askpermission:1.0.3'

如果您在支持库中遇到冲突，则

compile('com.kishan.askpermission:askpermission:1.0.3', {
    exclude group: 'com.android.support'
})

现在请求许可

new AskPermission.Builder(this)
    .setPermissions(Manifest.permission.READ_CONTACTS, Manifest.permission.WRITE_EXTERNAL_STORAGE)
    .setCallback(/* PermissionCallback */)
    .setErrorCallback(/* ErrorCallback */)
    .request(/* Request Code */);

授予权限的回调

  public void onPermissionsGranted(int requestCode) {
// your code  }

权限被拒绝的回调

 public void onPermissionsDenied(int requestCode) {
// your code}

ErrorCallbacks

public void onShowRationalDialog(PermissionInterface permissionInterface, int requestCode) {
// Alert user by Dialog or any other layout that you want.
// When user press OK you must need to call below method.
permissionInterface.onDialogShown();

}

public void onShowSettings(PermissionInterface permissionInterface, int requestCode) {
// Alert user by Dialog or any other layout that you want.
// When user press OK you must need to call below method.
// It will open setting screen.
permissionInterface.onSettingsShown();

}

如何在Android M中检查单个请求的多个权限？

16 个答案: