Question

你好，请帮我在登录过程中使用我的代码，这是一条错误信息

解析错误：语法错误，意外＆＃39;＆＃39; （T_ENCAPSED_AND_WHITESPACE），期待标识符（T_STRING）或变量（T_VARIABLE）或数字（T_NUM_STRING）

在$_SESSION['userid'] = $row['userid'];行

这是我的完整登录过程代码：

session_start(); 
$message = "";

if(count($_POST) > 0){
    $conn = mysql_connect("localhost", "root", "");
    mysql_select_db("etransmittal", $conn);
    $result = mysql_query("SELECT * FROM tbl_userlist WHERE username = '" . $_POST["username"] . "' AND user_password = '" . $_POST["password"] . "');
    $row = mysql_fetch_array($result);

    if(is_array($row)){
        $_SESSION['userid'] = $row['userid'];
        $_SESSION['username'] = $row['username'];
    }
    else{
        $message = "Invalid username or password";
    }
}

if(isset($_SESSION['userid'])){
    header("location: userhomepage.php");
}

Answer 1

你丢失了一个双引号，我修复了它：

$result = mysql_query("SELECT * FROM tbl_userlist WHERE username = '" . $_POST["username"] . "' AND user_password = '" . $_POST["password"] . "'");

Answer 2

<?php
    if( $_POST['submit_button']=='Login'  ) {

                        $userdata = "select * from usertbl WHERE username = '".$_POST['username']."'  ";
                        $res = mysql_query($userdata);
                        $userdata = mysql_fetch_array($res);
                        $userDetail = $userdata[0];

                        if(  ( $userDetail['username'] == $_POST['username'] )  &&  ( $userDetail['password'] == md5($_POST['password']) ) ){

                                $_SESSION['userid'] = $userDetail['id'];
                                $_SESSION['username'] = $userDetail['username'];
                                $_SESSION['useremail'] = $userDetail['email'];


                                header("Location:Dashboard.php");

                        }   else {
                                header("Location:index.php");
                        }
                }
?>

<form action="" method="POST">
    <input type="text" name="username" > 
    <input type="text" name="password" > 
    <input type="submit" name="submit_button" value="login"> 
</form>

登录进程解析错误：语法错误

2 个答案: