Question

{"data":{"tokenId":"cbad508f88a2a8ff47c75426338026de"},"success":true,"error":{"errorCode":"200","errorMsg":"successfully"}}
{"referredBy":"Dvbrhhv","deviceId":"488014664955832","msisdn":"8358808909"}

我想在php中只回显一下来自这个数据的tokenId我怎么能开始友好地帮助我

Answer 1

json不是valid json，请this link

检查你的json

$json='{
    "data": {
        "tokenId": "cbad508f88a2a8ff47c75426338026de"
    },
    "success": true,
    "error": {
        "errorCode": "200",
        "errorMsg": "successfully"
    }
}';

$json=json_decode($json);
echo $json->data->tokenId;

使用json_decode Demo

Answer 2

你可以得到它

$jsonResult = json_decode($json ,true);
echo $jsonResult['data']['tokenId'];

您可以看到result

<br/>

输出：cbad508f88a2a8ff47c75426338026de

想要从json数据中回显特定值

2 个答案: