Question

我想要做的是，如果我问一个问题只能回答是和不，我想确保答案是肯定还是否定。否则，它会停止。

 print("Looks like it's your first time playing this game.")
 time.sleep(1.500)
 print("Would you like to install the data?")
 answer = input(">").lower
 if len(answer) > 1:

    if answer == "no":
        print("I see. You want to play portably. We will be using a password system.")
        time.sleep(1.500)
        print("Your progress will be encrypted into a long string. Make sure to remember it!")
    else:
        print("Didn't understand you.")

elif len(answer) > 2:

    if word == "yes":
        print("I see. Your progress will be saved. You can back it up when you need to.")
        time.sleep(1.500)

else:
    print("Didn't understand you.")

Answer 1

类似的东西：

if word.lower() in ('yes', 'no'):

将是最简单的方法（假设情况无关紧要）。

侧面说明：

answer = input(">").lower

将lower方法的引用分配给answer，而不是调用它。您需要添加parens，answer = input(">").lower()。另外，如果这是Python 2，则需要使用raw_input，而不是input（在Python 3中，input是正确的。）

Answer 2

首先：

answer = input(">").lower

应该是

answer = input(">").lower()

其次，len(answer) > 1和"no"都是"yes"（对于那个问题，任何大于一个字符的东西都是如此）。永远不会评估elif块。如果不明显修改当前代码的逻辑，则应该改为：

if answer == 'no':
    # do this
elif answer == 'yes':
    # do that
else:
    print("Didn't understand you.")

python - 检查某些单词的字符串

2 个答案: