Question

我有一个Search page，用户可以根据特定条件进行搜索。我无法使查询正确显示只有一个所需的对象。它显示指定条件的多个条目。这是我们的数据库设置：

CREATE TABLE Class
    (       
        cid int NOT NULL,
        classNum int,
        classDept varchar(20),
        PRIMARY KEY (cid)
    );

CREATE TABLE Book
    (
        bid int NOT NULL,
        cid int NOT NULL,
        title varchar(20) NOT NULL, 
        author varchar(20) NOT NULL,
        isbn varchar(13),
        price decimal(5,2) NOT NULL,
        PRIMARY KEY (bid),
        FOREIGN KEY (cid) REFERENCES Class (cid)
    );

CREATE TABLE Contact
    (
        contactID int NOT NULL,
        fname varchar(20),
        lname varchar(20),
        contactInfo varchar(90) NOT NULL,
        PRIMARY KEY (contactID)
    );

CREATE TABLE Post
    (
        pid int NOT NULL,
        contactID int NOT NULL,
        bid int NOT NULL,
        postDate date,
        PRIMARY KEY (pid),
        FOREIGN KEY (contactID) references Contact(contactID),
        FOREIGN KEY (bid) references Book(bid)
    );

这是我们用来尝试根据用户输入的条件进行查询的php代码。

$author = $_POST["author"];
     $title = $_POST["title"];
     $classNum = $_POST["number"];
     $classDept = $_POST["department"];
     $isbn = $_POST["isbn"];


              $query = "SELECT title, author, isbn, price, classNum, classDept, contactInfo
           FROM Book, Class, Contact, Post
           WHERE Book.cid=Class.cid AND Contact.contactID=Post.ContactID and Book.bid=Post.bid AND Book.author='$author' OR Book.title='$title' ";
     $stid = oci_parse($conn,$query);
     oci_execute($stid,OCI_DEFAULT);

我们做错了什么？我们如何才能显示正确的搜索结果？

Answer 1

我不完全确定Oracle中的连接语法与mysql（这是构建和测试的内容）相同，但是给出了虚拟数据和对某些表的微小修改（将auto_increment添加到主键）返回与params匹配的预期两行。

create table if not exists `book` (
  `bid` int(11) not null auto_increment,
  `cid` int(11) not null,
  `title` varchar(64) not null,
  `author` varchar(20) not null,
  `isbn` varchar(13) default null,
  `price` decimal(5,2) not null,
  primary key (`bid`),
  key `cid` (`cid`),
  constraint `book_ibfk_1` foreign key (`cid`) references `class` (`cid`)
) engine=innodb auto_increment=5 default charset=utf8;

insert into `book` (`bid`, `cid`, `title`, `author`, `isbn`, `price`) values
    (1, 1, 'deranged dahlias', 'gertrude geikel', '1234-cdbs-9d', 250.00),
    (2, 1, 'mental magnolias', 'gertrude geikel', '4234-cdfg-9f', 225.00),
    (3, 1, 'raging roses', 'gertrude geikel', '4389-fkpl-8d', 120.25),
    (4, 3, 'peaceful petunias', 'alice cooper', '9043-dflk-01', 500.25);

create table if not exists `class` (
  `cid` int(11) not null auto_increment,
  `classnum` int(11) default null,
  `classdept` varchar(20) default null,
  primary key (`cid`)
) engine=innodb auto_increment=4 default charset=utf8;

insert into `class` (`cid`, `classnum`, `classdept`) values
    (1, 404, 'fookology'),
    (2, 403, 'forbidden fruits'),
    (3, 200, 'goodness');

create table if not exists `contact` (
  `contactid` int(11) not null auto_increment,
  `fname` varchar(20) default null,
  `lname` varchar(20) default null,
  `contactinfo` varchar(90) not null,
  primary key (`contactid`)
) engine=innodb auto_increment=3 default charset=utf8;

insert into `contact` (`contactid`, `fname`, `lname`, `contactinfo`) values
    (1, 'joe', 'bloggs', 'chief headbanger'),
    (2, 'fred', 'flintstone', 'potatopeeler');

create table if not exists `post` (
  `pid` int(11) unsigned not null auto_increment,
  `contactid` int(11) not null,
  `bid` int(11) not null,
  `postdate` date default null,
  primary key (`pid`),
  key `contactid` (`contactid`),
  key `bid` (`bid`),
  constraint `post_ibfk_1` foreign key (`contactid`) references `contact` (`contactid`),
  constraint `post_ibfk_2` foreign key (`bid`) references `book` (`bid`)
) engine=innodb auto_increment=3 default charset=utf8;

insert into `post` (`pid`, `contactid`, `bid`, `postdate`) values
    (1, 1, 1, '2015-12-02'),
    (2, 2, 4, '2015-12-02');

在mysql gui中运行查询 - 不确定oracle中的连接语法是否相同。

set @_author='alice cooper';
set @_title='mental magnolias';

select * from `book` b
    left outer join `class` c on c.`cid`=b.`cid`
    left outer join `post` p on p.`bid`=b.`bid`
    left outer join `contact` ct on ct.`contactID`=p.`contactID`
    where b.`title`=@_title or b.`author`=@_author;

或者，对于php

$author=$_POST['author'];
$title=$_POST['title'];

$sql="select * from `book` b
    left outer join `class` c on c.`cid`=b.`cid`
    left outer join `post` p on p.`bid`=b.`bid`
    left outer join `contact` ct on ct.`contactID`=p.`contactID`
    where b.`title`='{$title}' or b.`author`='{$author}';";

如何查询通过外键连接的多个表中的数据？

1 个答案: