如何在XmlWriter的帮助下使用具有多个表的数据集来编写XML文件？

Question

我正在使用数据集并将查询结果存储到该数据集中。 我的查询ID就像那样

String Query = @"SELECT * FROM TABLE1;
                 SELECT * FROM TABLE2;
                 SELECT * FROM TABLE3;";

我正在使用以下内容

XmlDocument relationSheepDoc = new XmlDocument();
    StringWriter sWriter = new StringWriter();
    XmlTextWriter xmlWriter = new XmlTextWriter(sWriter);
    DataSet oDataSet = new DataSet("RelationSheeps");
     oDataSet = sql.ExecuteSqlDataSet(Query);
    string fileContent = string.Empty;
       for (int i = 0; i < oDataSet.Tables.Count; i++)
        {
            oDataSet.Tables[i].WriteXml(xmlWriter, XmlWriteMode.WriteSchema);
            fileContent = sWriter.ToString();               

        }
        relationSheepDoc.LoadXml(fileContent);
        xmlWriter.Close();

        return relationSheepDoc;

它只写第一个表并生成异常 如何在同一个XML文件中编写所有三个表？ 帮帮我...

Answer 1

您应该立即编写整个DataSet，如下所示：

oDataSet.WriteXml(xmlWriter, XmlWriteMode.WriteSchema);