Question

我正在使用英雄联盟API ，我正试图从 JSON 文件中获取排名数据。但是，如果玩家不是等级30 ，他就没有他的档案。所以这里

def getRankedData(region, ID, APIkey):
    URL = "https://" + region + ".api.pvp.net/api/lol/" + region + "/v2.5/league/by-summoner/" + ID + "/entry?api_key=" + APIkey
    response = requests.get(URL)
    return response.json()

它不会获得 JSON 文件，因为它不存在。我该怎么做，如果 URL 不存在且没有JSON文件，则返回字符串。

在这里，我将数据返回到 HTML 页面。但这也不行。

 region = request.form['region']
 summonerName = request.form['summonerName']
 APIkey = "45afde27-b628-473f-9a94-feec8eb86094"
 types = request.form['types']
 responseJSON = getData(region, summonerName, APIkey)
 ID = responseJSON[summonerName]['id']
 ID = str(ID)
 responseJSON2 = getRankedData(region, ID, APIkey)
 if not responseJSON2:
     divisionName = "Unranked"
 else: 
     divisionName = responseJSON2[ID][0]['name']
 responseJSON3 = getChallengerPlayers(region, str(types), APIkey)
 challengerPlayers = responseJSON3['entries'][0]['wins']
 #print challengerPlayers

 return render_template('form_action.html', ID = ID, divisionName = divisionName, challengerPlayers = challengerPlayers)

我收到了这个错误：

Traceback (most recent call last)
File "C:\Python27\lib\site-packages\flask\app.py", line 1836, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python27\lib\site-packages\flask\app.py", line 1820, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python27\lib\site-packages\flask\app.py", line 1403, in      handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1817, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1477, in     full_dispatch_request
rv = self.handle_user_exception(e)
File "C:\Python27\lib\site-packages\flask\app.py", line 1381, in  handle_user_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1475, in     full_dispatch_request
rv = self.dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1461, in  dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "C:\Users\Hanisek\Documents\Visual Studio     2015\Projects\FlaskWebProject2\FlaskWebProject2\FlaskWebProject2\views.py", line 53, in hello
responseJSON2 = getRankedData(region, ID, APIkey)
File "C:\Users\Hanisek\Documents\Visual Studio 2015\Projects\FlaskWebProject2\FlaskWebProject2\FlaskWebProject2\views.py", line 21, in getRankedData
Open an interactive python shell in this framereturn response.json()
File "C:\Python27\lib\requests\models.py", line 805, in json
return complexjson.loads(self.text, **kwargs)
File "C:\Python27\lib\json\__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "C:\Python27\lib\json\decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Python27\lib\json\decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded

Answer 1

通过在浏览器中运行api url来检查api url返回的内容总是一个好主意。我猜它是因为信息不存在而返回404错误。

在这种情况下，我建议在继续进行JSON解析之前检查是否存在404错误。

请求有一个名为status_code的函数，如果有错误将返回404错误。示例代码：

r = request.get("API STRING")
if r.status_code != 404:
    r.json()

Answer 2

对LOL不太了解但是有一个原因是你不能让你的程序使用和if / then语句检查播放器的级别然后只检查json文件如果玩家的级别足够高有一个？

Answer 3

您可以尝试检查网址是否存在，JSON是否格式正确，或者页面是否抛出40X状态代码

try:
    r = requests.get("URL")
    assert r.status_code < 400
    return r.json()
except (ValueError, ConnectionError, AssertionError):
    return ''

如何检查url是否包含JSON文件

3 个答案: