我如何“签名”或“命名”行结果？ （PHP）

Question

我正在尝试获得前3个结果，并使每一行具体。 例如，

得票最多的人是第一名， 获得第二多选票的人是第二名， 得票率排名第三的是第三名，

然后我想对它们进行设计，我不知道从哪里开始。

有没有办法专门处理每一行'按行排序，如果行高于第二高然后*'？

这是我目前的代码：

                $filter = $_GET["filter"];
            if ($filter == "")  {
                $query = "SELECT * FROM toplist WHERE Serverversion > 0 ORDER BY Votes DESC";
            } else if ($filter == "custom") {
                $query = "SELECT * FROM toplist WHERE Servertype = 'custom' AND Serverversion > 0  ORDER BY Votes DESC";
            }  else if ($filter == "pvp")   {
                $query = "SELECT * FROM toplist WHERE Servertype = 'pvp' AND Serverversion > 0  ORDER BY Votes DESC";
            }  else if ($filter == "economy")   {
                $query = "SELECT * FROM toplist WHERE Servertype = 'economy' AND Serverversion > 0  ORDER BY Votes DESC";
            }  else if ($filter == "remake")    {
                $query = "SELECT * FROM toplist WHERE Servertype = 'economy' AND Serverversion > 0 ORDER BY Votes DESC";
            }  else if ($filter == "all")   {
                $query = "SELECT * FROM toplist WHERE Serverversion > 0 ORDER BY Votes DESC";
            }

            if ($result = $con->query($query)) {
                while ($toplist = $result->fetch_assoc()) {
                    echo '
                    <tr>
                        <td><img src="'.$toplist["Bannerlink"].'" width="468" height="60" /></td>
                        <td>'.ucfirst($toplist["Servername"]).'</td>
                        <td>'.ucfirst($toplist["Servertype"]).' (Rev. '.ucfirst($toplist["Serverversion"]).')</td>
                        <td>'.$toplist["Votes"].'</td>
                        <td><a href="'.$toplist["Serverwebsite"].'" target="blank" class="btn btn-primary">Visit Website</a></td>
                        <td><a href="profile.php?profile='.$toplist["ID"].'" class="btn btn-success">Visit profile</a></td>
                    </tr>
                    ';
                }
                $result->free();
            }

Answer 1

一种选择是使用在循环中递增的计数器。然后根据当前行的位置设置一个类。

arr.every(b => b)