JDBC ResultSet无法存储查询结果

时间:2015-12-01 16:58:27

标签: java oracle jdbc resultset

我目前正在尝试通过JDBC在Oracle数据库上运行查询。我在SQLDeveloper中测试了我的查询,但是当我尝试在Java程序中运行查询时,我的ResultSet rs.next()结果返回false(表示rs中没有存储任何内容)。

我的代码如下:

public static void testFunction() {
    Properties properties = new Properties();
    properties.put("user", "USERNAMEHERE");
    properties.put("password", "PASSWORDHERE");

    String URL = "jdbc:oracle:thin:@abc:123:def456";
    Connection conn = null;
    PreparedStatement stmt = null;
    ResultSet rs = null;
    String sqltxt = "SELECT a.MESSAGE, a.DATE, a.ID_NUM, b.MESSAGE, b.ANOTHER_ID FROM USER.SOME_TABLE_NAME a INNER JOIN USER.DIFFERENT_TABLE_NAME b on a.MESSAGE = b.MESSAGE where a.DATE= '1-December-2014' and b.ANOTHER_ID = 3 and a.ID_NUM IN(0, 100)";


    try {
        conn = DriverManager.getConnection(URL, properties);
        stmt = conn.prepareStatement(sqltxt, ResultSet.TYPE_FORWARD_ONLY, ResultSet.CONCUR_READ_ONLY);
        rs = stmt.executeQuery();
        System.out.println("Records exist? " + rs.next());
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try { if (rs != null) rs.close(); } catch (Exception e) {};
        try { if (stmt != null) stmt.close(); } catch (Exception e) {};
        try { if (conn != null) conn.close(); } catch (Exception e) {};
    }
}

我注意到每当我向sqltxt添加一个WHERE子句时,就是当我的rs.next()产生错误时。

如果我碰巧自己找到了解决方案,我会很感激任何见解。我会在这里发布。

编辑:这是与上面的BUT相同的代码,对sqltxt有不同的查询:

public static void testFunction() {
    Properties properties = new Properties();
    properties.put("user", "USERNAMEHERE");
    properties.put("password", "PASSWORDHERE");

    String URL = "jdbc:oracle:thin:@abc:123:def456";
    Connection conn = null;
    PreparedStatement stmt = null;
    ResultSet rs = null;
    String sqltxt = "SELECT MESSAGE FROM USER.SOME_TABLE WHERE DATE = '01-December-2015'";

    try {
        conn = DriverManager.getConnection(URL, properties);
        stmt = conn.prepareStatement(sqltxt, ResultSet.TYPE_FORWARD_ONLY, ResultSet.CONCUR_READ_ONLY);
        rs = stmt.executeQuery();
        System.out.println("Records exist? " + rs.next());
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try { if (rs != null) rs.close(); } catch (Exception e) {};
        try { if (stmt != null) stmt.close(); } catch (Exception e) {};
        try { if (conn != null) conn.close(); } catch (Exception e) {};
    }
}

1 个答案:

答案 0 :(得分:2)

您应该避免SQL文本中的硬编码日期。特别是对于Oracle,它需要大量的工作。这里有两个答案,一个使用硬编码日期,另一个正确利用PreparedStatement对象的强大功能:

日期内嵌

public static void testFunction() {
    Properties properties = new Properties();
    properties.put("user", "USERNAMEHERE");
    properties.put("password", "PASSWORDHERE");

    String URL = "jdbc:oracle:thin:@abc:123:def456";
    Connection conn = null;
    PreparedStatement stmt = null;
    ResultSet rs = null;
    String sqltxt = "SELECT MESSAGE FROM USER.SOME_TABLE WHERE DATE = to_date('01-December-2015', 'dd-month-yyyy')";

    try (Connection conn = DriverManager.getConnection(URL, properties);
        PreparedStatement stmt = conn.prepareStatement(sqltxt, ResultSet.TYPE_FORWARD_ONLY, ResultSet.CONCUR_READ_ONLY);
        ResultSet rs = stmt.executeQuery();) {

        System.out.println("Records exist? " + rs.next());
    } catch (Exception e) {
        e.printStackTrace();
    }
}

(有关Oracle中硬编码日期的更多信息,请参阅:http://www.techonthenet.com/oracle/functions/to_date.php

参数化SQL的日期

public static void testFunction() {
    Properties properties = new Properties();
    properties.put("user", "USERNAMEHERE");
    properties.put("password", "PASSWORDHERE");

    String URL = "jdbc:oracle:thin:@abc:123:def456";
    String sqltxt = "SELECT MESSAGE FROM USER.SOME_TABLE WHERE DATE = ?";

    try (Connection conn = DriverManager.getConnection(URL, properties);
        PreparedStatement stmt = conn.prepareStatement(sqltxt, ResultSet.TYPE_FORWARD_ONLY, ResultSet.CONCUR_READ_ONLY);
        ResultSet rs = stmt.executeQuery();) {

        stmt.setDate(1, Date.valueOf(LocalDate.now().withYear(2015).withMonth(12).withDayOfMonth(1)));
        System.out.println("Records exist? " + rs.next());
    } catch (Exception e) {
        e.printStackTrace();
    }
}

阅读:http://docs.oracle.com/javase/tutorial/jdbc/basics/prepared.html,了解有关在Java中使用参数化SQL的更多信息。