Question

我有以下查询，我需要修改它以使用symfony2。

SELECT someColumn, COUNT(*) AS n, 
SUM(IF(STATUS = 20,1,0)) AS sent 
FROM someTable 
WHERE ID = :id;

到目前为止我做了什么：

$query = ("SELECT myEntity.someField AS someColumn,
            SUM(CASE WHEN myEntity.status = '20' then 1 ELSE 0 END) as sent
            FROM AppRoot\MyBundle\Entity\MyEntity myEntity
            WHERE myEntity.id = :id
            ");

但我得到了可怕的错误：

Error: Expected Literal, got 'CASE'

Answer 1

假设您从EntityRepository调用它，您可以像这样实例\ Doctrine \ ORM \ QueryBuilder：

$em = $this->_em->createQueryBuilder();

接下来，您可以使用以下命令构建查询：

$qb->select(array(
    'myEntity.someField as someColumn',
    'count(myEntity) as n',
    'SUM(CASE WHEN myEntity.status = :status then 1 ELSE 0 END) as sent',
    ... // add all the columns you need
  ))
  ->from('AppRoot\MyBundle\Entity\MyEntity','MyEntity')
  ->where( $qb->expr()->eq('myEntity.id', ':id') )
  ->setParameters(array(
      'status'=>'20',
      'id' => $theEntityId
  ));

最后你可以像这样检索你的结果：

$qb->getQuery()->getResult();

或者如果您更喜欢普通的旧式数组：

$qb->getQuery()->getArrayResult();

这应该有效，您可以使用以下方法检查生成的查询：

$qb->getQuery()->getDQL(); // get the Doctrine Query Language query
$qb->getQuery()->getSQL(); // get the SQL generated query

错误：预期文字，得到'CASE'

1 个答案: