Question

我的查询如下：

我有一张表Table1

     SkillID            EmpCode
    ------------------------------
    2                   A101
    4                   A101
    5                   A101
    8                   A101
    4                   A102
    3                   A102
    1                   A102
    6                   A102
    5                   A102
    7                   A102

现在我必须选择没有SkillIDs 1,6和＆amp;的SELECT EmpCode。 7。在示例中，它应该将EmpCode A101 作为结果。 仅限不包含SkillID 1,6＆amp; amp;的Empire 7应该是结果

Answer 1

尝试：

SELECT EmpCode
FROM mytable
GROUP BY EmpCode
HAVING COUNT(CASE WHEN SkillID IN (1, 6, 7) THEN 1 END) = 0

Demo here

您也可以使用NOT EXISTS：

SELECT DISTINCT EmpCode
FROM mytable AS t1
WHERE NOT EXISTS (
  SELECT 1
  FROM mytable AS t2
  WHERE t1.EmpCode = t2.EmpCode AND t2.SkillID IN (1, 6, 7) )

Demo here

Answer 2

以下代码位于t-sql：

{{yy, mm, dd}, {hh, mi, ss}} = :calendar.universal_time
"~.4.0w~.2.0w~.2.0wT~.2.0w~.2.0w~.2.0wZ"
|> :io_lib.format([yy, mm, dd, hh, mi, ss])
|> IO.iodata_to_binary

选择对另一列的值没有特定值的行

2 个答案: