PHP，MySQL：在休假时显示用户＆＃39;

Question

我在下面的代码中有关于如何显示当前的人员＃34;休假时间＃34;今天。

$today = date("j F, Y");//date format is->1 December, 2015
$result = $db->query("SELECT name, date_apply, leave_from, leave_end, num_days, reason FROM applied_user  WHERE status = 'Approved' AND leave_from = '$today'");

我的问题是，是否可以在当天之前显示所有批准的假期？谢谢..

Answer 1

试试这个

$today = date('d F, Y'); //current date (11 December, 2015)
$result = $db->query(
    "SELECT name, date_apply, leave_from, leave_end, num_days, reason 
    FROM applied_user  
    WHERE status = 'Approved' 
    AND leave_from >= '$today'");

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