使用getline获取字符串并将其作为函数参数c ++传递

Question

嗨，我对c ++编程很陌生，所以请耐心等待。我有一个库txt文件，其中包含14本书及其作者。我正在尝试将此库加载到数组中，然后接受用户输入，以便按标题或作者姓名搜索库。到目前为止，这是我的代码......

#include <iostream>
#include <fstream>
#include <sstream>
#include <string>

using namespace std;

const int ARRAY_SIZE = 1000;
string bookTitle [ARRAY_SIZE];
string bookAuthor [ARRAY_SIZE];

int loadData(string pathname);
void showAll(int count);
int showBooksByAuthor (int count, string name);
int showBooksByTitle (int count, string title);


int main ()
{
    int numFound, nextNumFound, number, numOfBooks;
    char reply;
    string bookTitles[5], authorName[5], backupFile;
    cout << "Welcome to Brigham's library database." << endl;
    cout << "Please enter the name of the backup file:";
    cin >> backupFile;
    numOfBooks = loadData (backupFile);
    if (numOfBooks == -1) {
        cout << endl;
    } else {
        cout << numOfBooks << " books loaded successfully." << endl;
    }


    do {
        cout << "Enter Q to (Q)uit, Search (A)uthor, Search (T)itle, (S)how All: ";
        cin >> reply;
        switch (reply) {
            case 'a':
            case 'A':
                cout << "Author's name: ";
                cin.getline(authorName, 5);
                numFound = showBooksByAuthor(numOfBooks, authorName);
                cout << numFound << " records found.";
                cout << endl;
                break;
            case 'q':
            case 'Q':
                cout << endl;
                break;
            case 's':
            case 'S':
                showAll(numOfBooks);
                cout << endl;
                break;
            case 't':
            case 'T':
                cout << "Book title: ";
                getline(cin, bookTitles);
                numFound = showBooksByTitle(numOfBooks, bookTitles);
                cout << nextNumFound << " records found.";
                cout << endl;
                break;
            default:
                cout << "Invalid input" << endl;
                break;          
        }
    } while (reply != 'q' && reply != 'Q');
}


int loadData (string pathname){
    int count = 0, noCount = -1;
    ifstream inputFile;
    string line, reply;

    inputFile.open(pathname.c_str()); 

    if (!inputFile.is_open()) { //If the file does not open then print error message
        cout << "Unable to open input file." << endl;
        return noCount;
    }

        for (int i = 1; i < ARRAY_SIZE; i++) {
            getline(inputFile, bookTitle[i]);
            getline(inputFile, bookAuthor[i]);
            //cout << bookTitle[i] << endl;
            //cout << bookAuthor[i] << endl;    
            count++;
             if(inputFile.eof()) {
                return count;
             }
        }
}

void showAll (int count) {
    for (int j = 1; j <= count; j++) {
        cout << bookTitle[j] << endl;
        cout << bookAuthor[j] << endl;
    }
}

int showBooksByAuthor (int count, string name) {
    int numByAuthor;
    for (int k = 1; k <= count; k++) {
        if(name == bookAuthor[k]) {
            cout << bookTitle[k] << " (" << bookAuthor[k] << ")" << endl;
            numByAuthor++;
        }
    }
    return numByAuthor;
}

int showBooksByTitle (int count, string title) {
    int numByTitle;
    for (int i = 1; i <= count; i++) {
        if (title == bookTitle[i]) {
            cout << bookTitle[i] << " (" << bookAuthor[i] << ")" << endl;
            numByTitle++;
        }
    }
    return numByTitle;
}

所以我的问题是我的int showBooksByAuthor和int showBooksByTitle函数。目前，当用户输入't'或'a'按标题或作者查找书籍时，它甚至不会提示他们输入标题或作者，它只会自动吐出0条记录。在我将switch语句中的案例't'和案例'a'从getline(cin, stringname)更改为cin >> stringname后，就会出现此错误。我意识到，如果他们要输入大于1个字的任何输入，那么函数将失败，因为我知道cin读取第一个空格。但我不明白为什么getline功能不起作用。我代码中的任何想法？抱歉，如果格式错误。