Question

考虑下面的这个JSON对象：

{
   "cells":[
      {
         "count":"1",
         "gdp_growth__avg":1.90575802503285,
         "geo__name":"united states of america",
         "time":1990
      },
      {
         "count":"1",
         "gdp_growth__avg":9.17893670154459,
         "geo__name":"china",
         "time":1991
      },
      {
         "count":"1",
         "gdp_growth__avg":-5.04693945214571,
         "geo__name":"russia",
         "time":1991
      },
      {
         "count":"1",
         "gdp_growth__avg":-0.0622142217811472,
         "geo__name":"botswana",
         "time":1991
      },
      {
         "count":"1",
         "gdp_growth__avg":14.2407063986337,
         "geo__name":"china",
         "time":1992
      },
      {
         "count":"1",
         "gdp_growth__avg":-14.5310737731921,
         "geo__name":"russia",
         "time":1992
      },
      {
         "count":"1",
         "gdp_growth__avg":3.55494453739944,
         "geo__name":"united states of america",
         "time":1992
      },
      {
         "count":"1",
         "gdp_growth__avg":13.9643147001603,
         "geo__name":"china",
         "time":1993
      },
      {
         "count":"1",
         "gdp_growth__avg":-8.66854034194856,
         "geo__name":"botswana",
         "time":1993
      },
      {
         "count":"1",
         "gdp_growth__avg":2.74204850437989,
         "geo__name":"united states of america",
         "time":1993
      },
      {
         "count":"1",
         "gdp_growth__avg":4.04272516401846,
         "geo__name":"united states of america",
         "time":1994
      },
      {
         "count":"1",
         "gdp_growth__avg":13.0806818010789,
         "geo__name":"china",
         "time":1994
      },
      {
         "count":"1",
         "gdp_growth__avg":-12.5697559787493,
         "geo__name":"russia",
         "time":1994
      },
      {
         "count":"1",
         "gdp_growth__avg":10.9249803004994,
         "geo__name":"china",
         "time":1995
      },
      {
         "count":"1",
         "gdp_growth__avg":-4.14352840666389,
         "geo__name":"russia",
         "time":1995
      },
      {
         "count":"1",
         "gdp_growth__avg":2.71655384149574,
         "geo__name":"united states of america",
         "time":1995
      },
      {
         "count":"1",
         "gdp_growth__avg":10.0085233990531,
         "geo__name":"china",
         "time":1996
      },
      {
         "count":"1",
         "gdp_growth__avg":3.79848988541973,
         "geo__name":"united states of america",
         "time":1996
      }
]
}

我想映射和减少并生成一个新对象，其中包含上述JSON中所有国家的GDP增长总和，可能看起来大致如下：

{  
  {
     "gdp_growth__avg":46.23,
     "geo__name":"united states of america",
  },
  {
     "gdp_growth__avg":16.23,
     "geo__name":"china",
  },
  {
     "gdp_growth__avg":36.23,
     "geo__name":"russia",
  },
  {
     "gdp_growth__avg":26.23, 
     "geo__name":"botswana",
     "time":1991
  }
 }

我查看了map和reduce，我不确定如何最好地继续进行。

我认为这样的事情可能会朝着正确的方向发展，但似乎并没有达到我的期望：

      var arr = [{x:1},{x:2},{x:4}];

      arr.reduce(function (a, b) {
        return {x: a.x + b.x};
      });

      console.log(arr); //Outputs that same initial array

虽然我认识到在服务器端执行此操作可能更好更容易，但我想知道我尝试做什么可以在客户端使用JavaScript完成。有什么建议？提前致谢。

Answer 1

试试这个：

var data = { cells:[...] };

var r = data.cells.reduce(function(pv, cv) {
    if ( pv[cv.geo__name] ) {
        pv[cv.geo__name] += cv.gdp_growth__avg;
    } else {
        pv[cv.geo__name] = cv.gdp_growth__avg;
    }
    return pv;
}, {});

console.log(r);

输出示例：

    { 
      'united states of america': 18.76051995774611,
      'china': 71.39814330096999,
      'russia': -36.291297610751,
      'botswana': -8.730754563729707 
   }

Answer 2

Array.reduce方法不会更改数组对象，而是以新数组的形式返回结果。

Answer 3

您可以尝试这样的事情：

var data = {"cells": [...]};

data.cells.map(function(datum) {
  return {
    geo__name: datum.geo__name,
    gdp_growth__avg: data.cells.filter(function(o) {
      return o.geo__name === datum.geo__name;
    }).reduce(function(sum, o) {
      return sum + o.gdp_growth__avg;
    }, 0)
  };
})

毋庸置疑，您也可以从datum中提取其他属性，例如time。我没有。

Answer 4

我试图用更好的时间复杂度来做：

let ans = [];
let map = new Map();
ques.cells.forEach(x => {
if(map[x.geo__name]){
map.set(x.geo__name, map[x.geo__name] + x.gdp_growth__avg);
}else{
map.set(x.geo__name,x.gdp_growth__avg);
}
});

map.forEach((v,k)=>{
ans.push({"geo__name":k, "gdp_growth__avg":v});
});
ques.cells = ans;

解决方案如下：

[
  {
    "geo__name": "united states of america",
    "gdp_growth__avg": 3.79848988541973
  },
  {
    "geo__name": "china",
    "gdp_growth__avg": 10.0085233990531
  },
  {
    "geo__name": "russia",
    "gdp_growth__avg": -4.14352840666389
  },
  {
    "geo__name": "botswana",
    "gdp_growth__avg": -8.66854034194856
  }
]

使用JavaScript映射和减少JSON对象

4 个答案: