Coldfusion Lucee 4.5.2.018(Linux) - REST服务(不能转换String)JSON

时间:2015-11-30 19:14:56

标签: mysql web-services coldfusion railo lucee

致力于REST网络服务,我没有太多经验冷网络服务。这是非常基本的网络服务。如果你们能指出我,我做错了什么。这将是很大的帮助。

Application Server:Lucee 4.5.2.018(Linux)

请在下面找到我的代码。

组件功能/网络服务。

<cfcomponent rest="true" restpath="/hello">

    <cffunction name="formPost" access="remote" returnType="struct" httpMethod="POST" restPath="/name" hint="POST Method" produces="application/json">
           <cfargument name="firstname" type="String" restArgSource="Form">
           <cfargument name="lastname" type="String" restArgSource="Form">
         <cfset myStruct =  structnew()>  
           <cfset myStruct.FirstName = firstname>
           <cfset myStruct.LastName  = lastname>

            <cfquery name="Qry" datasource="myDSN">
                select col1,col2 from myTableData
            </cfquery>
           <cfset myJsonVar = serializeJSON(Qry) />
           <cfreturn myJsonVar>
    </cffunction>
</cfcomponent>

调用网络服务

<cfhttp url="http://mydev:8888/rest/Example/hello/name" method="POST"  result="res"  port="8888" >
        <cfhttpparam type="header" name="Accept" value="application/json">
        <cfhttpparam type="formfield" name="firstname" value="Dan">
        <cfhttpparam type="formfield" name="lastname" value="Gates">
</cfhttp>
<cfdump var="#res#">

问题: 定义returnType="struct"错误string can't cast String [{"COLUMNS":["COL1","COL2"],"DATA":[["0","7777777"],["0","888888"]]}] to a value of type [struct]

定义returnType="string"时没有错误"{\"COLUMNS\":[\"COL1\",\"COL2\"],\"DATA\":[[\"0\",\"7777777\"],[\"0\",\"888888\"]]}"

尝试在循环中获取[DATA]值

<cfloop from="1" to="#ArrayLen(d.DATA)#" index="i"> <cfloop from="1" to=#ArrayLen(d.DATA[i])# index="j"> <cfset resultSrt =d.COLUMNS[j]&" = " &d.DATA[i][j]> #resultSrt#<br> </cfloop> </cfloop>

消息:No matching property [DATA] found in [string] 堆栈跟踪:The Error Occurred in /opt/lucee/tomcat/webapps/ROOT/calling.cfm: line 52 50: 51: 52: <cfloop from="1" to="#ArrayLen(d.DATA)#" index="i"> 53: <cfloop from="1" to=#ArrayLen(d.DATA[i])# index="j"> 54: <cfset resultSrt =d.COLUMNS[j]&" = " &d.DATA[i][j]> Output

1 个答案:

答案 0 :(得分:1)

首先,在您返回查询后,您应该将returnType设置为Query

如果您将produces的{​​{1}}属性设置为cffunction,那么在这种情况下,您不需要在返回数据时执行显式JSON序列化。 ColdFusion会自动为您完成。你可以写:

application/json

要读取从服务返回的结果,您需要反序列化数据。像这样:

<cfreturn Qry />