Question

我有一种方法需要根据2 Map[Integer, Data]创建Sets。它是参数的一种合并，其中map中的键是集合中每个元组的键，值是Data使用元组值构造的对象。

def craete(included: Set[(Int, Set[Int])], excluded: Set[(Int, Set[Int])]) {
//create new Map[Integer, Data]...
}

和dataObject类：

class Data(included: Seq[Integer], excluded: Seq[Integer]) {
}

Answer 1

case class Data(included: Set[Int], excluded: Set[Int])

def create(included: Map[Int, Set[Int]], excluded: Map[Int, Set[Int]]): Map[Int, Data] = {
  val keys = included.keySet union excluded.keySet
  keys.iterator.map(id => id -> Data(
    included.getOrElse(id, Set.empty), 
    excluded.getOrElse(id, Set.empty))
  ).toMap
}

请注意，scala中没有Integer

mergin 2设置为聚合对象

1 个答案: