Question

以下是我尝试的示例代码。

<?php
require "init.php";
$json = file_get_contents('php://input'); 
//$data = json_decode($json,true);
// remove the ,true so the data is not all converted to arrays
$data = json_decode($json);
// Now process the array of objects
foreach ( $data as $inv ) {
    $custInfo = $inv->custInfo;
    $rate =     $inv->rate;
    $weight=    $inv->weight;
    $desc=      $inv->desc;
    $makingAmt= $inv->makingAmt;
    $vat=       $inv->vat;
    $itemTotal= $inv->itemTotal;
    $sum_total= $inv->sum_total;
    $barcode=   $inv->barcode;
    $net_rate=  $inv->net_rate;
    $date=      $inv->date;
    $invoiceNo= $inv->invoiceNo;
    $bill_type= $inv->bill_type;
    $sql = "INSERT INTO selected_items 
             (custInfo, invoiceNo, barcode, desc, 
              weight, rate, makingAmt,net_rate,
              itemTotal,vat,sum_total,bill_type,date) 
            VALUES
             ('$custInfo','$invoiceNo','$barcode','$desc',
              '$weight','$rate','$makingAmt','$net_rate',
              '$itemTotal','$vat','$sum_total','$bill_type','$date')";
    $res = mysql_query($sql,$con);
    if(!$res){
        $result = new stdClass();
        $result->status = false;
        $result->msg = mysql_error();
        echo json_encode($result);
        exit;
    }
}
?>

以下是来自server-link的json数据。

{
        name : 'scopeName',
        index : 'scopeName',
        width: '400px',
        resizable : true,
        align : "left",
        editable : true,
        edittype : "select",
        editoptions : {
            value : getSequenceNumbers()
        },
        editrules : {
            required : true
        }

function:

    function getSequenceNumbers() {
        alert("here123");
        $.getJSON("http://localhost:8039/ReleaseManagementApp/releasemgmt/config/Q2FY16/scope", null, function(data) {
        if (data != null) {
            alert("here");
            //construct string.  
            //(or the server could return a string directly)
            for (var i=0; i<data.length; i++) {
                sel.append('<option value="' + data[i].scopeName + '">' + data[i].scopeName + '</option>');
            }
        }
    });
}

我想知道我是否可以将scopeName从上面的响应填充到jqgrid作为选择标签。

Answer 1

相反，我建议您使用自定义格式化程序：

{
    name : 'scopeName',
    index : 'scopeName',
    width: '400px',
    resizable : true,
    align : "left",
    formatter:getSequenceNumbers // <----use the function here
}

现在你可以从这个函数返回一个select元素：

function getSequenceNumbers() {
        alert("here123");
        var sel = '<select>';
            sel +='<option value="select">Select...</option>';
        $.getJSON("url", null, function(data) {
        if (data != null) {
            alert("here");
            //construct string.  
            //(or the server could return a string directly)
            for (var i=0; i<data.length; i++) {
                sel += '<option value="' + data[i].scopeName + '">' 
                        + data[i].scopeName + '</option>';
            }
            sel +="</select>";
        }
    });
    return sel;
}

如何将日志添加到jqgrid列？

1 个答案: