我正在使用angularJs和rest控制器进行Web服务调用。我收到了400个不好的请求。当我提出更改用户状态的请求时,我收到错误。请找到以下js文件,控制器和UI代码。
Js控制器 -
var user=angular.module('userApp', ['ngAnimate']);
user.controller('userController',function($scope,$http){
var urlBase=window.location.pathname;
$scope.selection = [];
$scope.toggle=true;
$scope.statuses=['YES','NO'];
$scope.sortType= 'name'; // set the default sort type
$scope.sortReverse= false; // set the default sort order
$scope.searchUser= ''; // set the default search/filter term
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
//get all users and display initially
$http.get(urlBase+"/users")
.success(function(data){
$scope.users = data;
});
$scope.addUser = function addUser() {
if($scope.firstName=="" || $scope.lastName=="" || $scope.email == "" || $scope.mobile == ""|| $scope.status == ""){
alert("Insufficient Data! Please provide values for task name, description, priortiy and status");
}
else{
$http.post(urlBase + '/users/insert/' +$scope.firstName+'/'+$scope.lastName+'/'+$scope.email+'/'+$scope.mobile+'/'+$scope.status)
.success(function(data) {
$scope.users = data;
$scope.firstName="";
$scope.lastName="";
$scope.email="";
$scope.mobile="";
$scope.status="";
$scope.toggle='!toggle';
});
}
};
$scope.archiveUser = function archiveUser(id){
console.log(":: Value of id :"+id);
$http.post(urlBase+'users/archive/'+id)
.success(function(data) {
$scope.users = data;
console.log(":: Data updated and displayed.")
})
.failure(function(data){
alert("Failed to archieve task ::"+data);
});
};
});
用户界面中正在调用代码的部分,我使用ng-repeat显示值,然后单击调用archiveUser()的按钮。 Id值很好。
<button class="btn" ng-Click='archiveUser(x.id)'><i class="fa fa-archive"></i></button>
Spring Controller用于处理请求 -
@RequestMapping(value="users/archive/{userIds}",method = RequestMethod.POST,headers="Accept=application/json")
public List<User> archiveUser(@PathVariable int userId) {
User user = new User();
user=userService.getUserService(userId);
List<User> users=userService.getAllUserService();
return users;
}
答案 0 :(得分:0)
问题在于&#39;&#39;正如帕克曼评论的那样。我删除了&#39; s&#39;然后保存&amp;尝试过,得到了期待的正确结果。谢谢帕克曼。