Question

我的数组总和有问题。所以我有这个数组：

Array
(
[0] => Array
    (
        [totalGames] => 21
        [nature] => 542
    )

[1] => Array
    (
        [totalGames] => 2
        [nature] => 418
    )

[2] => Array
    (
        [totalGames] => 26
        [nature] => 728
    )

[3] => Array
    (
        [totalGames] => 3
        [nature] => 542
    )

[4] => Array
    (
        [totalGames] => 2
        [nature] => 418
    )

)

我想对此数组求和以获得此结果：

Array
(
[0] => Array
    (
        [totalGames] => 24
        [nature] => 542
    )

[1] => Array
    (
        [totalGames] => 4
        [nature] => 418
    )

[2] => Array
    (
        [totalGames] => 26
        [nature] => 728
   )
)

我试过这样：

while ($aRecord = $rResult->fetch_array(MYSQLI_ASSOC))
    {
        if($aData['nature'] == $aRecord['nature']){
            $aData[] = $aRecord;
        }else{
            $aData['nature']      =   $aRecord['nature'];
            $aData['totalGames']  +=  $aRecord['nature']['totalGames'];
        }
    }

但不行。我做错了什么？你能帮我吗？ Thx提前和抱歉我的英语。

我也试过但是没有用：

SELECT COUNT(*) as totalGames, nature FROM master WHERE date(date)="2015-11-20" GROUP BY nature ORDER by totalGames

Answer 1

您的代码应为：

$myArr = array(array('totalGames' => 21, 'nature' => 542),array('totalGames' => 2,'nature' => 418),array('totalGames' => 26,'nature' => 728), array('totalGames' => 3,'nature' => 542),array('totalGames' => 2,'nature' => 418));
$sum = array_reduce($myArr, function ($a, $b) {
    isset($a[$b['nature']]) ? $a[$b['nature']]['totalGames'] += $b['totalGames'] : $a[$b['nature']] = $b;  
    return $a;
});
print_r($sum);

Answer 2

尝试

while ($aRecord = $rResult->fetch_array(MYSQLI_ASSOC)){
    $hash = $aRecord['nature'];
    if(isset($aData[$hash])){
        $aData[$hash]['totalGames']  +=  $aRecord['totalGames'];
    }else{
        $aData[$hash]['nature']     =   $aRecord['nature'];
        $aData[$hash]['totalGames']  =   $aRecord['totalGames'];
    }
}

使用不同键求和2个数组

2 个答案: