Question

我需要序列化复杂List<List<byte[]>>。

我尝试了通常的XML序列化，并在里面找到了带有ArrayOfArrayOfBase64Binary复杂元素的正确XML文件。但是反序列化时我得到了例外 - System.InvalidOperationException: <ArrayOfArrayOfBase64Binary xmlns=''> didn't expected

这是获得的XML：

<?xml version="1.0"?>
<ArrayOfArrayOfBase64Binary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ArrayOfBase64Binary>
    <base64Binary>uWmpcJ5NsuN+kDdc7LHKeAQDRpt9tww2eQejjw==</base64Binary>
    <base64Binary>wkHfOzURrWoibj6ayvvLvP/MC69zitU/8/rC3A==</base64Binary>
    <base64Binary>io4VUpcqK0wjGx29KEUtaoB0mM4ezVVPCwwiVQ==</base64Binary>
    .... 
    <base64Binary>VB7qwOVZVzqIP2aDvEd5BqPmseMvDDt+6jJC2A==</base64Binary>
    <base64Binary>bBH7CSP0e2zEDBTpOjqEPXZS5GhQ+21Aa6L9sQ==</base64Binary>
    <base64Binary>g3CKGhBT9oJHn3xJCAtFL9bM+7IJCPXdJIqysg==</base64Binary>
    <base64Binary>4o+aIxOu9xZ1EX/+KvaifPjyDNhBgtPZshbjUg==</base64Binary>
    </ArrayOfBase64Binary>
  <ArrayOfBase64Binary>
    <base64Binary>4h92Duu+R8UH9seJpmDoboVVOk6YOy8GV0eCtw==</base64Binary>
    <base64Binary>Oe2g/IRc5NbYZqmB/zNEx5V4kelnDpy3rjrrwg==</base64Binary>
    <base64Binary>YMtYeQ3izUkQGrybfVWIzaTpVOvS0ItRN+/I4Q==</base64Binary>
    ....
    <base64Binary>K1cYC737a7vqLvyJtq3JcR06w3ih6c2s+Ocq+g==</base64Binary>
    <base64Binary>4Gc/Em29D2GZ0vm65gg65fypYficzNvG9wNvTQ==</base64Binary>
    <base64Binary>SEHpodvPphyyJlLqoMM2sTWWKnJ9yDz+JkUwCQ==</base64Binary>
    <base64Binary>NS5+EwbsGPOMQlkQvg8lllNi/9vaA6SxnX0nUw==</base64Binary>
  </ArrayOfBase64Binary>
</ArrayOfArrayOfBase64Binary>`

序列化/反序列化的代码：

//Serialize
using (var stream = File.Create("Levin/RandomData/Z.xml"))
{
    var serializer = new XmlSerializer(typeof(List<List<byte[]>>));
    serializer.Serialize(stream, _Z_ext);
}

//Deserialize
using (var stream = File.OpenRead("Levin/RandomData/Z.xml"))
{
    var serializer = new XmlSerializer(typeof(List<List<byte[]>>));
    _Z_ext = (List<List<byte[]>>)serializer.Deserialize(stream);
}

Answer 1

如果你可以使用smth而不是xml：

序列化：

    var binFormatter = new BinaryFormatter();
    var fileStream = File.Create(fileName);
    binFormatter.Serialize(fileStream, yourListOfLists);
    fileStream.Close();

并反序列化：

    var binFormatter = new BinaryFormatter();
    var fileStream = File.Open(fileName, FileMode.Open);
    var yourListOfLists = (List<List<byte[]>>)binFormatter.Deserialize(fileStream);
    fileStream.Close();

Answer 2

对我而言，它运作良好。可能取决于您的数据。请试试这个：

public partial class Form1 : Form
{
    List<List<byte[]>> _Z_ext = new List<List<byte[]>>();

    public Form1()
    {
        InitializeComponent();
    }

    private void LoadB_Click(object sender, EventArgs e)
    {
        using (var stream = System.IO.File.OpenRead("Z.xml"))
        {
            var serializer = new System.Xml.Serialization.XmlSerializer(typeof(List<List<byte[]>>));
            _Z_ext = (List<List<byte[]>>)serializer.Deserialize(stream);
        }
    }

    private void SaveB_Click(object sender, EventArgs e)
    {
        // Create some data
        byte[] b1 = new byte[2] { 64, 65 };
        List<byte[]> l1 = new List<byte[]>();
        l1.Add(b1);
        _Z_ext.Add(l1);

        byte[] b2 = new byte[2] { 66, 67 };
        List<byte[]> l2 = new List<byte[]>();
        l2.Add(b2);
        _Z_ext.Add(l2);

        using (var stream = System.IO.File.Create("Z.xml"))
        {
            var serializer = new System.Xml.Serialization.XmlSerializer(typeof(List<List<byte[]>>));
            serializer.Serialize(stream, _Z_ext);
        }
    }
}

有用吗？如果您使用数据怎么办？

如何序列化复杂的数据列表？

2 个答案: