我是swift adn中的新手我在swift中遇到initwithcoder问题。
我有类UserItem,我需要它来保存用户登录。
目标c中的就像这样
import java.util.Scanner;
public class Assignment7 {
public static int row, col;
public static Scanner scan = new Scanner(System.in);
public static char[][] board = new char[3][3];
public static char turn = 'X';
static Scanner input = new Scanner(System.in);
public static void main(String[] args) {
/*create for-loop
* 9 empty spots, 3x3
*/
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
board[i][j] = '_';
}
}
Play();
}
public static void Play() {
//find if game over
boolean playing = true;
PrintBoard();
while (playing) {
System.out.println("Please enter a row, then a column: ");
//make row next thing player types
row = scan.nextInt() - 1;
//same with column
col = scan.nextInt() - 1;
board[row][col] = turn;
if (GameOver(row, col)) {
playing = false;
System.out.println("Game over! Player " + turn + " wins!");
}
PrintBoard();
//switch players after entries
if (turn == 'X') {
turn = 'O';
} else {
turn = 'X';
}
}
}
public static void PrintBoard() {
for (int i = 0; i < 3; i++) {
System.out.println();
for (int j = 0; j < 3; j++) {
//get dividers on left
if (j == 0) {
System.out.print("| ");
}
// get dividers in all
System.out.print(board[i][j] + " | ");
}
}
//enter space after board
System.out.println();
}
public static boolean GameOver(int rMove, int cMove) {
// Check perpendicular victory
if (board[0][cMove] == board[1][cMove]
&& board[0][cMove] == board[2][cMove]) {
return true;
}
if (board[rMove][0] == board[rMove][1]
&& board[rMove][0] == board[rMove][2]) {
return true;
}
// Check diagonal victory
if (board[0][0] == board[1][1] && board[0][0] == board[2][2]
&& board[1][1] != '_') {
return true;
}
return false;
}
}
在swift中,我试着这样做
- (id)initWithCoder:(NSCoder *)decoder{
if (self = [super init]){
self.username = [decoder decodeObjectForKey:@"username"];
}
return self;
}
但如果像上面那样,我会收到代码错误
override init() {
super.init()
}
required init(coder decoder: NSCoder!) {
self.username = (decoder.decodeObjectForKey("username")?.stringValue)!
super.init(coder: decoder)
}
错误信息是&#34;额外的参数&#39;编码器&#39;在电话中
我无法理解,所以我试试这段代码,
super.init(coder: decoder)
但是,得到错误
convenience init(decoder: NSCoder) {
self.init()
self.username = (decoder.decodeObjectForKey("username")?.stringValue)!
}
我该怎么办?谢谢你的帮助。
答案 0 :(得分:12)
我在过去与NSCoding
(你用来归档和取消归档对象的协议)进行了斗争,我发现你正在经历同样的痛苦。希望这会减轻一点:
class UserItem: NSObject, NSCoding {
var username: String
var anInt: Int
init(username: String, anInt: Int) {
self.username = username
self.anInt = anInt
}
required init?(coder aDecoder: NSCoder) {
// super.init(coder:) is optional, see notes below
self.username = aDecoder.decodeObjectForKey("username") as! String
self.anInt = aDecoder.decodeIntegerForKey("anInt")
}
func encodeWithCoder(aCoder: NSCoder) {
// super.encodeWithCoder(aCoder) is optional, see notes below
aCoder.encodeObject(self.username, forKey: "username")
aCoder.encodeInteger(self.anInt, forKey: "anInt")
}
// Provide some debug info
override var description: String {
get {
return ("\(self.username), \(self.anInt)")
}
}
}
// Original object
let a = UserItem(username: "michael", anInt: 42)
// Serialized data
let data = NSKeyedArchiver.archivedDataWithRootObject(a)
// Unarchived from data
let b = NSKeyedUnarchiver.unarchiveObjectWithData(data)!
print(a)
print(b)
重要的是匹配encodeWithCoder(aCoder:)
(归档函数)和init(coder:)
(unarchive函数)中的键和数据类型。
初学者的困惑在于如何处理超类。如果超类本身符合NSCoding
,则只应在上述两个函数中包含超类。 NSObject
本身不提供。这个想法是每个类都知道它自己的属性,其中一些是私有的。如果超类无法归档/取消归档,则无需调用它们。