由于某种原因,我收到错误“React-无法读取未定义的属性'setState'”。因此,this.state永远不会使用用户输入的值进行更新。当我尝试注释掉的绑定时,我得到了奇怪的行为,我无法输入用户名的输入,我不再得到null错误,但值只是未定义。任何帮助,将不胜感激。感谢。
import __fetch from "isomorphic-fetch";
import React from "react";
import InlineCss from "react-inline-css";
import Transmit from "react-transmit";
import Header from './components/header'
class Registration extends React.Component {
componentWillMount () {
if (__SERVER__) {
console.log("Hello server from Registration");
}
if (__CLIENT__) {
console.log("Hello Registration screen");
}
}
constructor () {
super()
this.state = {
name: '',
password: ''
}
//this.onChangeName = this.onChangeName.bind(this);
//this.onChangePassword = this.onChangePassword.bind(this);
}
onChangeName(e) {
//this.state.name = e.target.name
this.setState({ name: e.target.name});
}
onChangePassword(e) {
//this.state.password = e.target.name
this.setState({ password: e.target.password });
}
emptinessChecker(){
let {name, password} = this.state
console.log(name)
if (name === "" || password === "") {
return true;
}
else {
return false;
}
}
submit() {
console.log(this)
console.log(this.state)
if (this.emptinessChecker()){
alert("Please do not leave any fields blank!");
}
else{
var xhr = new XMLHttpRequest(); // new HttpRequest instance
xhr.open("POST", "/edit");
xhr.addEventListener("load", e => {
console.log(xhr.responseText)
});
xhr.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
xhr.send(JSON.stringify(this.state));
window.location.href= "/success"
}
}
render () {
//let {username, password} = this.state
if (__SERVER__) {
console.log("render server from registration");
}
if (__CLIENT__) {
console.log('we client now!')
}
return (
<InlineCss stylesheet={Registration.css()} namespace="Registration">
<Header />
<div>
<div className = "Register" >
Register
</div>
<ul className="account-fields">
<div className = 'Name'>
<label>Username</label>
<input type="text" value={this.state.name} onChange={this.onChangeName} />
</div>
<div className = 'Password'>
<label>Password</label>
<input type="password" value={this.state.password} onChange={this.onChangePassword} />
</div>
<div className='submitForm'>
<div className='submit' onClick={e=>this.submit()}>Submit</div>
</div>
</ul>
</div>
</InlineCss>
);
}
/**
* <InlineCss> component allows you to write a CSS stylesheet for your component. Target
* your component with `&` and its children with `& selectors`. Be specific.
*/
static css () {
return (`
& .Register {
position: fixed;
right: 550px;
bottom: 550px;
font-size: 50px;
}
& .account-fields {
position: fixed;
right: 550px;
bottom: 450px;
font-size: 20px;
}
& .submitForm {
position: fixed;
right: 10px;
bottom: 10px;
width: 200px;
}
& .submit {
cursor: pointer;
text-align: center;
font-size: 20px;
padding: 10px;
background-color: #00E4A5;
color: #fff;
border-radius: 5px;
box-shadow: 0 2px 10px 0 rgba(0,0,0,.13);
border-bottom: 2px solid #00C791;
text-shadow: 0px -1px 0px #009E73;
}
`);
}
}
export default Transmit.createContainer(Registration);
答案 0 :(得分:13)
在这些事件处理程序中,e.target
是触发事件的<input>
。
onChangeName(e) {
//this.state.name = e.target.name
this.setState({ name: e.target.name});
}
onChangePassword(e) {
//this.state.password = e.target.name
this.setState({ password: e.target.password });
}
您可以使用其value
属性获取输入值:
onChangeName(e) {
this.setState({name: e.target.value});
}
onChangePassword(e) {
this.setState({password: e.target.value});
}
根据构造函数中已注释掉的代码,您还需要确保this
绑定正确。
如果您为输入提供了合适的name
道具,则可以使用单个onChange
处理程序替换它们:
constructor(props) {
super(props)
// ...
this.onChange = this.onChange.bind(this)
}
onChange(e) {
this.setState([e.target.name]: e.target.value})
}
render() {
// ...
<input type="text" name="name" value={this.state.name} onChange={this.onChange}/>
<input type="password" name="password" value={this.state.password} onChange={this.onChange}/>
// ...
}
答案 1 :(得分:5)
如果您要在构造函数中遵循绑定模式,请确保使用正确的构造函数调用:
constructor (props) {
super(props)
在构造函数中注意props
。
由于您似乎正在使用ES6组件定义,因此您应该在呈现的组件中绑定到this
:
<input type="text" value={this.state.name} onChange={this.onChangeName.bind(this)} />
您无需在构造函数中定义此内容:
//this doesn't work
//this.onChangeName = this.onChangeName.bind(this);
//this.onChangePassword = this.onChangePassword.bind(this);
看起来也许你在你的例子中遗漏了一些代码,所以我不确定你是否试图摆脱不必要的部分为了示例或什么,但要确保你的组件是结构合理。
答案 2 :(得分:0)
如果使用箭头功能,则无需绑定。
onNameChange = (e)=> {
this.setState({name:e.target.value});
}
onPasswordChange = (e) => {
this.setState({password:e.target.value});
}