Question

我有三个键盘快捷键，我正在尝试添加到我的iPad程序中。这是三个

        // add the "change Status" keyboard shortcut
    let statusShortcut = UIKeyCommand(input: "s", modifierFlags: UIKeyModifierFlags.Command, action: "changeStatusPressed:", discoverabilityTitle: "Change Status of Meeting")
    addKeyCommand(statusShortcut)

    // add the "add user" keyboard shortcut
    let addShortcut = UIKeyCommand(input: "+", modifierFlags: UIKeyModifierFlags.Command, action: "addButtonPressed:", discoverabilityTitle: "Add Participant to Meeting")
    addKeyCommand(addShortcut)

    // add the "remove user" keyboard shortcut
    let removeShortcut = UIKeyCommand(input: "-", modifierFlags: UIKeyModifierFlags.Command, action: "removeButtonPressed:", discoverabilityTitle: "Remove Participant to Meeting")
    addKeyCommand(removeShortcut)

当我按下键盘上的Command键时，只有后两个被识别并显示在屏幕叠加层中。此外，只有第二个工作。

所有动作都已正确定义。建议将不胜感激。

Answer 1

好的，我对此比较陌生，但我认为你做错了。而不是你正在做的事情，做到这一点。

在ViewDidLoad之后（外部）执行所有操作：

override func canBecomeFirstResponder() -> Bool {
return true
}

override var keyCommands: [UIKeyCommand]? {
    return [

UIKeyCommand(input: "S", modifierFlags: .Command, action: "changeStatusPressed:", discoverabilityTitle: "Change Status of Meeting"),
UIKeyCommand(input: "+", modifierFlags: .Command, action: "addButtonPressed:", discoverabilityTitle: "Add Participant to Meeting"),
UIKeyCommand(input: "-", modifierFlags: .Command, action: "removeButtonPressed:", discoverabilityTitle: "Remove Participant from Meeting"),

   ]
}

func changeStatusPressed(sender: UIKeyCommand) {
    print("command-s selected")
    // code for changeStatusPressed
}

func addButtonPressed(sender: UIKeyCommand) {
    print("command+ selected")
    // code for addButtonPressed
}

func removeButtonPressed(sender: UIKeyCommand) {
    print("command- selected")
    // code for removeButtonPressed
}

你的问题可能是你的函数中不正确的大写，或语法，或完全不同的东西！我希望这会对你有所帮助（对不起，这么晚）。

为什么这三个中只有两个addKeyCommand的工作

1 个答案: