简称XML:
...
<team>
<capitan>Zdeno Chara</capitan>
<alernativeCapitan>
<player>Zdeno Chara</player> <!-- NO Chara, he's the capitan obviously -->
<player>Someone Else</player>
<player>Someone Other</player>
</alernativeCapitan>
</team>
<team>
<capitan>Abc Edf</capitan>
<alernativeCapitan>
<player>Abc Xyz</player>
<player>Bac Edf</player>
<player>Abc 123</player>
</alernativeCapitan>
</team>
...
问:如何在XPath中比较一个字符串(capitan)和序列(alternativeCapitan)?
我想知道capitain是否也像其他capitan / player一样。仅在一个团队中进行比较。 (如果是这样,那就错了。这就是全部,如果结果是布尔值或数字则无关紧要。)
感谢。
答案 0 :(得分:2)
这个问题对我来说不是100%明确,也许你想要这样的事情:
//team[capitan=alernativeCapitan/player]
<强> xpathtester demo
强>
上述XPath将返回team
元素中capitan
列出alternativeCapitan
的所有team
。或者,如果您想要相反的情况,则返回capitan
中alternativeCapitan
不是的所有//team[not(capitan=alernativeCapitan/player)]
:
<table id="example" class="display table" style="width: 100%; cellspacing: 0;">
<thead>
<tr>
<th>Code</th>
<th>Name</th>
<th>Hours</th>
<th>Class</th>
<th>Add</th>
</tr>
</thead>
<tfoot>
<tr>
<th>Code</th>
<th>Name</th>
<th>Hours</th>
<th>Class</th>
<th>Add</th>
</tr>
</tfoot>
<tbody>
<?php
$query = "SELECT * FROM class";
$result = mysqli_query($connection,$query) or die ("Couldn’t execute query.");
while($row = mysqli_fetch_assoc($result))
{
echo "<tr>
<td>$row[code]</td>
<td>$row[name]</td>
<td>$row[hours]</td>";
$query1 = "SELECT total FROM classtot where code='$row[code]'";
$result1 = mysqli_query($connection,$query1);
while ($row=mysqli_fetch_assoc($result1))
{
$a=$row['total'];
}
$alphabet = range('A','Z');
$i = 1;
echo "
<td><select id='selectError' data-rel='chosen' name='class'>";
while ($i<=$a)
{
$kls=$alphabet[$i-1];
echo "<option value=$kls> $kls </option>";
$i=$i+1;
}
echo "</select></td>
<td>
<a class='btn btn-primary btn-addon m-b-sm btn-xs' href='home_member.php?page=add&id=$row[code]'>
<i class='fa fa-plus'></i> Add</a>
</td>
</tr>";
}
?>
</tbody>
</table>