Question

＆GT;这是代码 。

我想搜索数据库中的每个单词，但结果只显示单个关键字而不是多个。 它是一个PDO数据库当我搜索 facebook 这样的单词时，会显示结果如果我搜索两个或多个单词搜索，则结果不会出现。

＆＃39;

function getResults(){
 $q=$GLOBALS['q'];
 $p=$GLOBALS['p'];
 $start=($p-1)*10;
 if($p!=null){
  $starttime = microtime(true);
  $sql=$GLOBALS['dbh']->prepare('SELECT title, url, description FROM search WHERE `title` LIKE :q OR `url` LIKE :q OR `description` LIKE :q ');
  $sql->bindValue(":q", "%$q%");
  $sql->execute();
  $trs=$sql->fetchAll(PDO::FETCH_ASSOC);
  $endtime = microtime(true);
  if($sql->rowCount()==0 || $start>$sql->rowCount()){
   return 0;
  }else{
   $duration = $endtime - $starttime;
   $res=array();
   $res['count']=$sql->rowCount();
   $res['time']=round($duration, 4);
   $limitedResults=array_slice($trs, $start, 12);
   foreach($limitedResults as $r){
    $res["results"][]=array($r['title'], $r['url'], $r['description']);
   }
   return $res;
  }
 }
}
?>

＆＃39;

Answer 1

不确定为什么你没有使用@david strachan的方法（我认为这是一个非常好的解决方案），但我会尝试解释你也可以使用的一个选项并理解为什么你＆＃ 39;目前没有得到任何结果。

此时发生的情况是，您将这些值发送到您的查询中，最终成为;

SELECT title, url, description FROM search WHERE `title` LIKE `google+facebook+yahoo` OR `url` LIKE `google+facebook+yahoo` OR `description` LIKE `google+facebook+yahoo`

我不认为你想要找到包含所有这些的小东西。

我不确定如何使用查询来编写此内容，但您可以使用快速解决方案。

将值插入数组（google + facebook + yahoo）
使用循环从创建的数组中选择每个键并将其传递给查询
将查询添加的结果作为数组

Answer 2

您必须构建动态查询才能搜索两个单词。在下面的代码中，我使用GET来说明构建查询以显示查询和数组。我尽可能使用未命名的参数?和“延迟”绑定 - 将数据传递给执行以方便。

//Using GET here for testing

<?php
//Using GET here for testing
if(isset($_GET['q'])){
$q = $_GET['q'];
//}
//First split string
if (strpos($q, ' ') > 0) {
$pieces = explode(" ", $q);
//echo count($pieces);  
//You need an array to store columns
$columnArray = array( "title", "url", "description");
//You need an array to store parameters
$paramArray =array();
$clause = "WHERE";
}
//You need to build a dynamic query to perform this. Start with a basic stub

    $sql = "SELECT `title`, `url`, `description` FROM search ";

//Start building the query
//Also see PDO WIKI for use % in placeholders.ie placeholders cannot represent an arbitrary part of the query, but a complete data literal only
//Loop through columns
        foreach ($columnArray  as $column) {
            //$sql .
            foreach ($pieces as $value) {
                $sql .= " $clause $column LIKE ?";
            $clause = "OR";
            array_push($paramArray,"%$value%");
            }
} 

//echo query and parameter array
echo $sql;
echo "<br>";  
print_r($paramArray);

//Prepare and execute query 
//  $sth = $db->prepare($sql);
//  $sth->execute($paramArray);
}
?>

结果来自 xxx.php？q = google amazon quora 或者xxx.php？q = google + amazon + quora

    SELECT `title`, `url`, `description` FROM search WHERE title LIKE ? OR title LIKE ? OR title LIKE ? OR url LIKE ? OR url LIKE ? OR url LIKE ? OR description LIKE ? OR description LIKE ? OR description LIKE ?
Array ( [0] => %google% [1] => %amazon% [2] => %quora% [3] => %google% [4] => %amazon% [5] => %quora% [6] => %google% [7] => %amazon% [8] => %quora% )

Answer 3

这里是您发现有用的完整脚本。

 <?php  
                 if(isset($_GET["search"]))  
                 {  
                      $condition = '';  
                      //$query = explode(" ", $_GET["search"]);
                      $query = explode(" ", $_GET["search"]);

                      foreach($query as $text)  
                      {  
                           $condition .= "`title`  LIKE +'%".mysqli_real_escape_string($connect, $text)."%' OR ";  
                      }  
                      $condition = substr($condition, 0, -4);  
                      $sql_query = "SELECT * FROM countries2 WHERE " . $condition;  
                      $result = mysqli_query($connect, $sql_query);  
                      if(mysqli_num_rows($result) > 0)  
                      {  
                           while($row = mysqli_fetch_array($result))  
                           {  
                                echo '<tr><td>'.$row["title"].'</td></tr>';  
                           }  
                      }  
                      else  
                      {  
                           echo '<label>Data not Found</label>';  
                      }  
                 }  
                 ?>

我如何在Mysql数据库中搜索多字搜索

3 个答案: