Question

我将数组php转换为json，如下所示：

var jsoncsv = '<?php echo json_encode($csvData); ?>';
console.log(jsoncsv);

那些json的输出如下：

{"1":
{" NO":"    1",
 "EIR IN":"1545053   ",
 "CONT":"EOLU 1111111",
 "TYPE":"XXXX",
 "INDEPO":"21-11-2015",
 "JAM":"13:00",
 "KODE VSL":"ABO",
 "VESSEL":"ALBERT OLDENDORFF   ",
 "VOY":"N001   ",
 "CONSIG":"ASTABUMI CIPTA      ",
 "COND IN":"DMG",
 "CLEAN":"DIRTY",
 "TARE":"  2400",
 "GROSS":" 20000",
 "KAPASITAS":"  5000",
 "EX CARGO":"FOOD                ",
 "LAST AIR)":"  -  -    ",
 "LAST HIDRO":"  -  -    ",
 "MANU":"10-11  ",
 "BUILDER":"                    ",
 "OWNER":"APL                 "},

"2":
{" NO":"    2",
 "EIR IN":"1545052   ",
 "CONT":"EOLU 1234567",
 "TYPE":"IM04",
 "INDEPO":"21-11-2015",
 "JAM":"10:00",
 "KODE VSL":"202",
 "VESSEL":"WAN HAI 202         ",
 "VOY":"N 001  ",
 "CONSIG":"ANUGERAH AGUNG LUMIN",
 "COND IN":"AVL",
 "CLEAN":"DIRTY",
 "TARE":"  2400",
 "GROSS":" 20000",
 "KAPASITAS":"  1000",
 "EX CARGO":"MAKANAN             ",
 "LAST AIR)":"  -  -    ",
 "LAST HIDRO":"  -  -    ",
 "MANU":"11-13  ",
 "BUILDER":"                    ",
 "OWNER":"APL                 "}}

我选择了ON HTML：

<select data-placeholder="Masukkan EIR"  id="search" >
     <?php
        foreach ($csvData as $v) {
             echo '<option value ='. $v['NO'].' >' . $v['EIR IN'] . '- ' . $v['CONT'] . '</option>';
         }
     ?>
</select>

使用jquery，我管理了select选项。代码看起来像这样：

$(document).on("change", '#search', function(){ 
        var selected = $('#search').val() ;
        /*Passed the selected data, search in json*/
});

假设，选择option.val为2，如何获得json的所有“2”元素，如NO，EIR IN？

Answer 1

这有效：

$(document).on("change", '#search', function(){ 
        var selected = $('#search').val();
        var json = <?php echo json_encode($csvData) ?>;
        alert(json[selected]['EIR IN']);
});

您的HTML部分应如下所示：

<select data-placeholder="Masukkan EIR"  id="search" >
     <?php
        foreach ($csvData as $v) {
             echo '<option value ='. $v[' NO'].' >' . $v['EIR IN'] . '- ' . $v['CONT'] . '</option>';
         }
     ?>
</select>

请注意，这里有差距 - ＆gt; “NO”，所以你的json中没有“NO”元素

使用jquery访问基于json元素的select选项

1 个答案: