Question

最好的方法是设置一组键/值对（从MySQL获得）作为选择字段＆＃39;选择＆＃39;在控制器内？我想类似于：

 $form = $this->createForm(new AddNews(), $news);
 $newsList = $this->getDoctrine()
             ->getRepository('BakaMainBundle:News')->getAllNews();

 $titlesList = ...($newsList); // some fuction that extract title=>id 
                               // array from news object collection

 $form->get('newsList')->setData($titlesList);

AddNews（）表单如下所示：

public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add(...)
            ->add(...)
            ->add('accept' , 'submit')
            ->add('newsList', 'choice', array
            (
                'mapped' => false,
                'required' => true
            ));
    }

Answer 1

也许类似下面（假设Symfony＆gt; = 2.7）。有关字段选项，请参阅docs：

public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add(...)
            ->add(...)
            ->add('accept' , 'submit')
            ->add('newsList', 'entity', array
            (
                'class' => ''BakaMainBundle:News'',
                'choice_label' => 'title',
                'mapped' => false,
                'required' => true
            ));
    }

Answer 2

你可以得到你的新闻＆＃34;直接从您的formType文件，使用您的存储库，如：

    private function getNews(){    
    $newsList = $this->getDoctrine()
                 ->getRepository('BakaMainBundle:News')->getAllNews();

     $titlesList = ...($newsList); // some fuction that extract title=>id 
                                   // array from news object collection
    }

    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add(...)
            ->add(...)
            ->add('accept' , 'submit')
            ->add('newsList', 'choice', array
            (
                'mapped' => false,
                'required' => true,
                'choices' => $this->getNews()
            ));
    }

如何在Symfony2中设置选择字段值？

2 个答案: