Question

我正在创建一个从用户获取值的程序，然后使用sqlite3数据库将该值附加到db文件。但是在将值插入输入框时会发生奇怪的错误。

import sqlite3,time,datetime
from Tkinter import *

def create_table():
    conn = sqlite3.connect("medicaps.db")
    c = conn.cursor()
    c.execute("CREATE TABLE data(NAME TEXT,ENROLLMENT_NUMBER INT,MARKS INT,GRADE TEXT,UNIXTIME REAL ,DATETIME TEXT)")



class Application(Frame):


    def __init__(self,master):
        Frame.__init__(self,master)
        self.grid()
        self.create_widgets()



    def create_widgets(self):
        Label(self,text = "Welcome to the database entry program.").grid(row = 0,column = 0,columnspan = 2,sticky = W)

        Label(self,text = "Name : ").grid(row = 1,column = 0,sticky = W)
        Label(self,text = "Enrollment number : ").grid(row = 2,column = 0,sticky = W)
        Label(self,text = "Marks : ").grid(row = 3,column = 0,sticky = W)
        Label(self,text = "Grade : ").grid(row = 4,column = 0,sticky = W)

        self.name = Entry(self)
        self.name.grid(row = 1,column = 1)

        self.number = Entry(self)
        self.number.grid(row = 2,column = 1)

        self.marks = Entry(self)
        self.marks.grid(row = 3,column = 1)

        self.grade = Entry(self)
        self.grade.grid(row = 4,column = 1)

        self.text = Text(self,width = 35,height = 25,wrap = WORD)
        self.text.grid(row = 6,column = 0,columnspan = 2,sticky = W)

        Button(self,text = "Submit",command = self.reveal).grid(row = 5,column = 0,sticky = W)

    def reveal(self):
        conn = sqlite3.connect("medicaps.db")
        c = conn.cursor()
        unix = time.time()
        date = str(datetime.datetime.fromtimestamp(int(time.time())).strftime("%Y-%M-%d %H:%M:%S"))
        name = self.name.get()
        number = self.number.get()
        marks = self.marks.get()
        grade = self.grade.get()

        self.text.insert(0.0,"yoyo")

        try:
            number = int(number)
        except(ValueError):
            error_n = "Invalid Input"
            self.number.insert(0.0,error_n)

        try:
            marks = int(number)
        except(ValueError):
            error_m = "Invalid Input"
            self.marks.insert(0.0,error_m)

        c.execute("INSERT INTO data(NAME,ENROLLMENT_NUMBER,MARKS,GRADE,UNIXTIME,DATETIME) VALUES = (?,?,?,?,?,?)",
                  (name,number,marks,grade,unix,date))
        conn.commit()
        message = "Value appended successfully"
        self.text.delete(0.0,END)





root = Tk()


root.title("Dataentry")
root.geometry("500x750")

frame = Application(root)

root.mainloop()

引发了以下错误

File "C:\Python27\lib\lib-tk\Tkinter.py", line 1536, in __call__
    return self.func(*args)
  File "C:\Users\sahib navlani\Desktop\New folder\vdsf.py", line 62, in reveal
    self.number.insert(0.0,error_n)
  File "C:\Python27\lib\lib-tk\Tkinter.py", line 2517, in insert
    self.tk.call(self._w, 'insert', index, string)
  TclError: bad entry index "0.0"

Answer 1

错误正在告诉您问题的确切原因。 0.0是一个糟糕的索引。 self.number是Entry，索引是从零开始的整数。

您还尝试对Text窗口小部件使用相同的索引，这也是无效的。 Text窗口小部件索引是＆lt; line＆gt;格式的字符串（不浮点数）。＆lt; char＆gt; ，其中＆lt; line＆gt ; 是从1（一）开始的数字编号，＆lt; char＆gt; 以0（零）开头。因此，Text窗口小部件的第一个索引是字符串"1.0"。

Answer 2

阅读与您的代码相关的追溯。 self.number是一个Entry（）。此fine reference中定义了一个条目索引，我建议人们加入书签。由于Entry小部件包含单行文本，因此这样的索引是单个int。请尝试使用0代替0.0。

在Python tkinter Entry框中插入值时出错

2 个答案: