Question

我必须编写一个程序，从键盘读取一行数字并将它们保存到一个数组中，数字必须写成一行，我写了这个但由于无限循环而无法工作建议？

int main() {

    int numCasos = 0, contNumCasos = 0, numElem = 0;
    string aux;
    cout << "Number of cases: " << endl;
    cin >> numCasos;
    while (contNumCasos < numCasos) {

        cout << "Number of elements: " << endl;
        cin >> numElem;
        cout << "Enter the Elements separated by space: " << endl;
        cin.ignore();
        vector.cont = 0;
        int i = 0;
        while ((vector.cont < numElem) && getline(cin,aux,' ')){
            vector.v[i] = stoi(aux);
            vector.cont++;
            i++;
        }
    }

    cout << sumaBuenos(vector) << endl;
    cin.ignore();
    system("pause");
    return 0;
}

一个例子：
控制台：元素数量：
用户：4
控制台：输入按空格分隔的元素：
用户：2 43 65 56
- 这必须是矢量
- vector.v [0] = 2
- vector.v [1] = 43
- vector.v [2] = 65
- vector.v [3] = 56

Answer 1

通过修改可行。

int main() {

    int numCasos = 0, contNumCasos = 0, numElem = 0;
    string aux;
    cout << "Numero de casos: " << endl;
    cin >> numCasos;
    while (contNumCasos < numCasos) {

        cout << "Numero de elementos: " << endl;
        cin >> numElem;
        cout << "Ingrese los elementos separados por espacios: " << endl;
        cin.ignore();
        vector.cont = 0;
        getline(cin, aux);
        istringstream iss(aux);
        for (int i = 0;i < numElem;i++) {
            iss >> aux;
            vector.v[i] = stoi(aux);
            vector.cont++;
        }
        cout << sumaBuenos(vector) << endl;
        contNumCasos++;
    }

    system("pause");
    return 0;
}

遇到同样问题的人。

Answer 2

如果你知道你需要阅读多少个数字，那么有一个更简单的方法：

int n;
cin>>n; // how many numbers;
vector<int> v(n);
for ( int i=0; i<n; ++i ){
    cin>>v[i];
}

Answer 3

#include<iostream>
using namespace std; 

int main() 
{   
    int n;
    cout << "input numbers" << endl;
    cin >> n; 

    vector<int> v(n);

    for ( int i=0; i<n; ++i )
    {

        cin >>v[i];

    } 
    return 0; 

}

Answer 4

#include <bits/stdc++.h> 
#include<iostream>

using namespace std; 
  
int main() 
{
    int sizeofarray;
    cin >> sizeofarray;
    int a[sizeofarray];
    int i;

for (i = 0; i < sizeofarray; ++i)
{
    cin >> a[i];
}
    return 0; 
}

读取以空格分隔的输入数字并保存到数组

4 个答案: