我目前正在尝试执行一些MySQL查询并使用bind_params将结果保存到数组中,用于2个参数:userUniqueId (String)
和limit (used to LIMIT query records)
。我试图自己做,但似乎代码不能正常工作。我尝试过不同的方法,但仍然没有。你能帮我吗?查询工作正常,因为我已经在phpMyAdmin中测试了它我要编写的函数必须将记录提取到数组中然后我希望json_encode
该数组使用该数组作为函数的结果。
这是我的功能代码:
public function getUserFavouriteRecipes($user_unique_id, $limit) {
$stmt = $this->conn->prepare("SELECT recipe.`unique_id`, recipe.`title`, recipe.`img_tumbnail_link`, recipe.`add_date`, recipe.`kitchen_type`, recipe.`meal_type`, user.`name`, user.`surname`,
(SELECT count(*) from `like` WHERE recipe.`unique_id` = `like`.`recipe_unique_id_fk`) AS like_count
FROM `recipe`
JOIN `favourite` ON (recipe.`unique_id` = `favourite`.`recipe_unique_id_fk`)
JOIN `user` ON (recipe.`user_unique_id_fk` = user.`unique_id`)
WHERE favourite.`user_unique_id_fk` = ?
ORDER BY recipe.`add_date` DESC
LIMIT ?, 10");
$converted_limit = intval($limit);
$stmt->bind_param("si", $user_unique_id, $limit);
$result = $stmt->execute();
if ($result) {
$myArray = array();
// Fetching Rows From Query
while ($row = $result->get_result()->fetch()) {
$myArray[] = $row;
}
$stmt->close();
return $myArray;
} else {
return NULL;
}
}
我在这里尝试编码:
<?php
require_once 'include/DB_Functions.php';
$db = new DB_Functions();
// Receiving The Post Params
$user_unique_id = $_POST['user_unique_id_fk'];
$limit = $_POST['limit'];
// Getting Result Array
$resultArray = $db->getUserFavouriteRecipes($user_unique_id, $limit);
echo json_encode($resultArray);
?>
提前感谢您的帮助。
答案 0 :(得分:1)
使用预准备语句获取结果的正确方法是:
...
$stmt->execute();
$myArr = array();
$tmp = array();
$stmt->bind_result($tmp['unique_id'], $tmp['title'], ...); // all fields in select
$i = 0;
while($stmt->fetch()) {
$myArr[$i] = $tmp;
$i++;
}
if (count($myArr) > 0) {
return $myArr;
} else {
return false;
}
答案 1 :(得分:0)
您可以使用PDOStatement::fetchAll()
返回包含所有结果集行的数组,如下所示:
public function getUserFavouriteRecipes($user_unique_id, $limit) {
// your code
$stmt->execute();
return $stmt->fetchall(PDO::FETCH_ASSOC);
}
$resultArray = $db->getUserFavouriteRecipes($user_unique_id, $limit);
要对结果进行编码,您可以这样做:
$json=json_encode($resultArray);
如果你想显示结果,你可以这样做:
//loop over the $resultArray, setting $result to an array representing each row
foreach($resultArray as $result){
//loop over each $result (row), setting $key to the column name and $value to the value in the column.
foreach($result as $key=>$value){
//echo the key and value.
echo "{$key} = {$value}<br>";
}
}
<强>编辑:强>
public function getUserFavouriteRecipes($user_unique_id, $limit) {
// your code
$status = $stmt->execute();
$myArray = array();
if($status){
// Extract result set and loop rows
$result_set = $stmt->get_result();
while($result = $result_set->fetch_assoc()){
$myArray[] = $result;
}
return $myArray;
}else{
return NULL;
}
}
$resultArray = $db->getUserFavouriteRecipes($user_unique_id, $limit);
$json = json_encode($resultArray);
您的问题在于:
以下说明了带有两个参数的LIMIT
子句语法:
SELECT
column1,column2,...
FROM
table
LIMIT offset , count;
让我们检查LIMIT
子句参数:
offset
指定要返回的第一行的偏移量。第一行的offset
为0,而不是1. count
指定要返回的最大行数。 因此,您获得此string '[]' (length=2)
结果的原因是因为它无法根据您的offset
和count
获取任何记录。强>
试试这个:
public function getUserFavouriteRecipes($user_unique_id, $limit) {
$stmt = $this->conn->prepare("SELECT recipe.`unique_id`, recipe.`title`, recipe.`img_tumbnail_link`, recipe.`add_date`, recipe.`kitchen_type`, recipe.`meal_type`, user.`name`, user.`surname`,
(SELECT count(*) from `like` WHERE recipe.`unique_id` = `like`.`recipe_unique_id_fk`) AS like_count
FROM `recipe`
JOIN `favourite` ON (recipe.`unique_id` = `favourite`.`recipe_unique_id_fk`)
JOIN `user` ON (recipe.`user_unique_id_fk` = user.`unique_id`)
WHERE favourite.`user_unique_id_fk` = ?
ORDER BY recipe.`add_date` DESC
LIMIT ?");
$converted_limit = intval($limit);
$stmt->bind_param("si", $user_unique_id, $converted_limit);
$status = $stmt->execute();
$myArray = array();
if($status){
// Extract result set and loop rows
$result_set = $stmt->get_result();
while($result = $result_set->fetch_assoc()){
$myArray[] = $result;
}
return $myArray;
}else{
return NULL;
}
}
$resultArray = $db->getUserFavouriteRecipes($user_unique_id, $limit);
$json = json_encode($resultArray);
//var_dump($json);