我有一个具有许多属性的类,这些属性是服务器端逻辑所必需的,但是UI中需要一些属性。现在,当我从类创建一个json时,所有属性都写入json。我只想在转换为json时忽略某些值。我试过@JsonIgnore
。但它没有用。
我的班级
import com.fasterxml.jackson.annotation.JsonIgnore;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonProperty;
@JsonIgnoreProperties(ignoreUnknown = true)
public class Student {
@JsonProperty("id")
protected Integer id;
@JsonProperty("name")
protected String name;
/**
* This field I want to ignore in json.
* Thus used @JsonIgnore in its getter
*/
@JsonProperty("securityCode")
protected String securityCode;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@JsonIgnore
public String getSecurityCode() {
return securityCode;
}
public void setSecurityCode(String securityCode) {
this.securityCode = securityCode;
}
}
我正在使用
写这篇文章public static StringBuilder convertToJson(Object value){
StringBuilder stringValue = new StringBuilder();
ObjectMapper mapper = new ObjectMapper();
try {
stringValue.append(mapper.writeValueAsString(value));
} catch (JsonProcessingException e) {
logger.error("Error while converting to json>>",e);
}
return stringValue;
}
My Expected json should contain only :
id:1
name:abc
but what I am getting is
id:1
name:abc
securityCode:_gshb_90880..some_value.
这里有什么问题,请帮忙
答案 0 :(得分:2)
您的@JsonProperty
注释会覆盖@JsonIgnore
注释。从@JsonProperty
删除securityCode
,将生成所需的json输出。
如果您想要更高级的忽略/过滤,请查看:
@JsonView
:http://wiki.fasterxml.com/JacksonJsonViews
@JsonFilter
:http://wiki.fasterxml.com/JacksonFeatureJsonFilter