Question

您好我有PHP代码编码数组，我希望我的Android应用程序接收数组并存储到本地变量

服务器端的PHP代码：

echo json_encode(array('result'=>$result));

如何让android从服务器接收数组。我正在考虑使用Volley libray，但不知道如何实现

应该是这样的：

ArrayList eventdetail = repond(url...)

Answer 1

我相信你需要时间去研究。好像你刚刚开始。

他们有很多方法可以做到这一点。

您可以使用Rest API或SOAP API，无论您感觉如何。或者您可以在Android上构建自己的http客户端，以便从Web服务器请求和接收数据。

一切顺利。

对于SOAP，您可以使用

为了实施Volley，这是Ksoap2。

Answer 2

使用下面的代码来解析json数组

               JSONParser jParser = new JSONParser();

                JSONObject json = jParser.getJSONFromUrl(url);

                JSONArray jArrayVersion = json.getJSONArray("result");

                for (int j = 0; j < jArrayVersion.length(); j++) {

                    JSONObject items = jArrayVersion.getJSONObject(j);

                    String namesv = items.getString("name");
                    String message = items.getString("message");

                   }

// JSONParser类

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.BasicHttpParams;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
import org.json.JSONException;
import org.json.JSONObject;

import android.util.Log;

    public class JSONParser {

        static InputStream is = null;
        static JSONObject jObj = null;
        static String json = "";

        // constructor
        public JSONParser() {

        }

        public JSONObject getJSONFromUrl(String url) {
            List<NameValuePair> params = new ArrayList<NameValuePair>();
            // Making HTTP request
            try {
                // defaultHttpClient
                HttpClient httpclient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost(url);
                System.out.println("url " + url);
                HttpParams httpParameters = new BasicHttpParams();
                // Set the timeout in milliseconds until a connection is established.
                // The default value is zero, that means the timeout is not used. 
                 int timeoutSocket = 6000;
                HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
                DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
                System.out.println("url " + url);
                httpPost.setEntity(new UrlEncodedFormEntity(params));
                System.out.println("url0 " + url);
                HttpResponse httpResponse = httpclient.execute(httpPost);
                System.out.println("url1 " + url);
                HttpEntity httpEntity = httpResponse.getEntity();
                System.out.println("url2 " + url);
                is = httpEntity.getContent();           

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            try {
                BufferedReader reader = new BufferedReader(new InputStreamReader(
                        is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                is.close();
                json = sb.toString();
            } catch (Exception e) {
                Log.e("Buffer Error", "Error converting result " + e.toString());
            }

            // try parse the string to a JSON object
            try {
                jObj = new JSONObject(json);
            } catch (JSONException e) {
                Log.e("JSON Parser", "Error parsing data " + e.toString());
            }

            // return JSON String
            return jObj;

        }
    }

如何从PhP服务器Android应用程序获取JsonArray？

2 个答案: