Question

在mysql中有3个表，如下所示：

ACCOUNT_SIGNUP_FORM_CLASS

我可以使用这个sql来查询这样的信息：

CREATE TABLE tstudent(
  id varchar(36) primary key not null,
  firstname VARCHAR(30) NOT NULL,
  lastname VARCHAR(30)  NOT NULL,
  grade int   NOT NULL,
  sex VARCHAR(1)      NOT NULL,
  birthday DATE,
  dayorboarding VARCHAR(1)    NOT NULL,
  age int   ,
  house VARCHAR(20),
  mentor VARCHAR(50)
);


CREATE TABLE ttrip(
  id varchar(36) primary key not null,
  departureday       DATE         NOT NULL,
  name varchar(100) not null unique
);

CREATE TABLE tsignup(
  id varchar(36) primary key not null,
  s_id varchar(36) not null,
  FOREIGN KEY (s_id) REFERENCES tstudent(id), 
  t_id varchar(36) not null,
  FOREIGN KEY (t_id) REFERENCES ttrip(id),
  departuretransport   VARCHAR(1)   NOT NULL,
  returntransport    VARCHAR(1)   NOT NULL,
  remark TEXT
);

但是当像这样使用hql时，它不起作用：

mysql> select * from tsignup where t_id in (select id from ttrip where  name like '%bar%');
... ignore data ...  
1 row in set (0.00 sec)

系统打印如下：

@Override
public DataGrid datagrid(Signup signup) {
    DataGrid dg = new DataGrid();

    String hql = "from Tsignup t";  
    Map<String, Object> params = new HashMap<String, Object>(); 
    hql = addWhere(signup, hql, params);

    String totalHql = "select count(*) " + hql; 
    hql = addOrder(signup, hql);
    List<Tsignup> l = signupDao.find(hql, params, signup.getPage(), signup.getRows());
    List<Signup> nl = new ArrayList<Signup>();
    changeModel(l, nl);
    dg.setTotal(signupDao.count(totalHql, params));
    dg.setRows(nl);
    return dg;
}

private String addWhere(Signup signup, String hql, Map<String, Object> params) {

    if(signup !=null){
        hql += " where 1=1 ";
        if(signup.getName() != null  && !signup.getName().trim().equals("")){
            hql += " and t.id in (select trip.id from ttrip as trip where trip.name like :name)";
            params.put("name", "%%" + signup.getName().trim() + "%%");
        }

    }
// logger will print:
    logger.info(signup.getName());
    logger.info(hql);

    return hql;
}

想知道在Hql中使用相同的sql的正确方法是什么。

Answer 1

找到解决方案：

    String hql = "from Tsignup t";      
    Map<String, Object> params = new HashMap<String, Object>(); 
    hql = addWhere(signup, hql, params);

...

        hql += " where 1=1 ";
        if(signup.getName() != null  && !signup.getName().trim().equals("")){
            hql += " and t.ttrip.id in (select id from Ttrip where name like :name)";
            params.put("name", "%%" + signup.getName().trim() + "%%");

HQL在子查询和子句中不起作用

1 个答案: