Question

我正在尝试从文件大小为100 Kb的服务器读取数据。所以我打破了数据并发送了6个文件。我可以在服务器上看到文件被正确分解为5个100 kb的块，其余的是74 kb左右。在客户端我试图接收这6个文件，所以我保持缓冲区大小为100但我得到7个文件。这是我的代码的一部分

try {
        sock = new Socket(server, port);
        System.out.println("Connecting...");
        int buffer = 100 * 1000, bytesRead = 0, counter = 0;

        // receive file
        BufferedInputStream bis = new BufferedInputStream(sock.getInputStream(), buffer);
        byte[] mybytearray = new byte[buffer];
        while ((bytesRead = bis.read(mybytearray))!=-1) {
                String fileName = "C:/Users/Desktop/Client2/" + counter;
                File newFile = new File(fileName);
                BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(newFile));
                bos.write(mybytearray, 0, bytesRead);
                bos.flush();
                bos.close();

                System.out.println("File " + counter + " downloaded (" + bytesRead + " bytes read)");
            counter++;
        }

    }

我得到的结果就是这个。

File 0 downloaded (35040 bytes read)
File 1 downloaded (100000 bytes read)
File 2 downloaded (100000 bytes read)
File 3 downloaded (100000 bytes read)
File 4 downloaded (100000 bytes read)
File 5 downloaded (100000 bytes read)
File 6 downloaded (39346 bytes read)

我做错了什么？

Answer 1

套接字根据缓冲区大小不读取

它应该在哪里说？来自Javadoc：

从输入流中将最多 [我的重点] len个字节的数据读入一个字节数组。

通过单个连接发送多个文件的正确方法是here。

socket根据缓冲区大小不读

1 个答案: