将URL查询变量传递给不同的表单

Question

我需要将用户从php表单发送到另一个表单，但我也需要传递一个URL查询。所以他们来到example.com/Form1.php$email=Whatever@Whatever.com，然后他们需要传递给example.com/Form2.php$email=Whatever@whatever.com。我无法在标题周围使用$ _GET（'Location：http://www.example.com'）;

参见代码

<?php

$email = $_GET["email"];

$_POST['customerSatisfaction'];
    $to = "blah";
    $email_from = 'blah';
    $email_subject = "blah";
    $headers = "From: $email_from \r\n";
    $email_body =   "   <?xml version = \"1.0\"?>
    <?adf version = \"1.0\"?>
        <adf>

            <prospect>
                <customer>

                <email preferredcontact=\"1\">$email</email>

                </customer>

            </prospect>
        </adf>
";
    mail($to,$email_subject,$email_body,$headers);
    header('Location: http://www.BLAH.com/NEED $EMAIL HERE!!');
?>

Answer 1

您发布的内容无效。试试这个：

header('Location: http://www.BLAH.com/?email=' . urlencode($email));

此外，在发送重定向标头后添加exit;通常也是一个好主意。