HTTP状态404请求的资源不可用

时间:2015-11-27 22:10:00

标签: jsp tomcat

我收到错误HTTP状态404的描述:请求的资源不可用。我不知道出了什么问题! 我在MySql Workbench中使用netbeans,我用一个表(lista)创建了一个模式(spesa)。

<%@page import="java.sql.ResultSetMetaData"%>
<%@page import="java.sql.SQLException"%>
<%@page import="java.util.Date"%>
<%@page import="java.sql.ResultSet"%>
<%@page import="java.sql.Statement"%>
<%@page import="java.sql.Connection"%>
<%@page import="java.sql.DriverManager"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>JSP Page</title>
</head>
<body>
    <h1>Lista della spesa</h1>
<%
        Class.forName("com.mysql.jdbc.Driver");

         String dburl = "jdbc:mysql://localhost/spesa?user=spesa&password=spesa";

         Connection con = DriverManager.getConnection(dburl);

         Statement st = con.createStatement();
         String sql = "SELECT voce,data,ordine FROM lista ORDER BY ordine";

         ResultSet res = st.executeQuery(sql);

        out.println ("<table>");

        while (res.next () ) {
            String voce = res.getString("voce");
            Date data = res.getDate("data");
            int ordine = res.getInt("ordine");

            out.println("<tr><td>"
                    + voce + "</td><td>"
                    + data + "</td><td>"
                    + ordine + "</td></tr>");
        }

        out.println ("</table>");


        st.close ();

        con.close ();
    %>
</body>

0 个答案:

没有答案