Question

在我的系统中，我有一个类，其中加载了（20？）final booleans，定义了此用户类型的权限。

有什么更好的方法可以做到这一点？

我确定有很多这方面的例子，但我不知道关键字。

Answer 1

您可以利用枚举，例如：

public enum Permission {
    READ, WRITE;
}

public class User {

    private final EnumSet<Permission> permissions;

    public User(Permission... permissions) {
       this.permissions = EnumSet.copyOf(Arrays.asList(permissions));
    }

    public boolean hasPermission(Permission permission) {
        return permissions.contains(permission);
    }

    //...
}

User user = new User(Permission.READ, Permission.WRITE);

Answer 2

创建一个类Permission，并为每个User提供一个集合。如果权限在用户的权限集合中，则用户具有该权限，否则不具有权限。

Answer 3

你可以使用这个掩码

public interface IPersmisions {

 public static final int NONE = 1 << 0;
 public static final int LEVEL1 = 1 << 1;
 public static final int LEVEL2 = 1 << 2;
 public static final int LEVEL3 = 1 << 3;
 public static final int LEVEL4 = 1 << 4;
 public static final int LEVEL5 = 1 << 5;
 public static final int LEVEL6 = 1 << 6;
 public static final int LEVEL7 = 1 << 7;
 public static final int LEVEL8 = 1 << 8;
 public static final int LEVEL9 = 1 << 9;
}

使用中你添加

int permisions = IPersmisions.NONE;

    public boolean checkPermission(int permission) {
        return (permissions & permission) != 0;
    }

    public void addPermission(int permission) {
            permissions = (permissions | permission);
    }

    public void removePermission(int permission) {
        permissions = (permissions & ~permission);
    }

比您可以为用户设置一个轻松设置的组

public interface IPermisionGroup extends IPermisions {

  public static final int LEVEL1_2_3 = LEVEL1 | LEVEL2 | LEVEL3; 
  public static final int LEVEL4_5_6 = LEVEL4 | LEVEL5 | LEVEL6; 
  public static final int LEVEL7_8_9 = LEVEL7 | LEVEL8 | LEVEL9; 

}

在您可以使用的代码中就像这样

   user.addPermision(IPermisions.LEVEL1);

或

   user.addPermision(IPermisions.LEVEL1 | IPermision.LEVEL2);

或

user.addPermision(IPermisionGroup.LEVEL1_2_3);

Answer 4

@tdammers建议的完整示例：

class enum Permission {
    WRITE, READ, EXECUTE, GROUP, OWNER
}

public class User {
    protected Set<Permission> permissions;

    public User() {
        permissions = new EnumSet<Permission>();
    }

    public boolean hasPermission(Permission p) {
        return permissions.contains(p);
    }

    public void addPermisssion(Permission p) {
        permissions.add(p);
    }

    public void removePermisssion(Permission p) {
        permissions.remove(p);
    }
}

//usage
User u = new User();
u.addPermission(Permission.READ);
System.out.writeln(u.hasPermission(Permission.WRITE));
u.removePermission(Permission.READ);

Answer 5

如果您不了解关键字和语法，可能需要阅读有关Java的书籍或在线进行一些教程。但是，一个类看起来像这样：

public class User {

private final boolean admin, superuser, guest;

public User(boolean admin, boolean superuser, boolean guest) {
    this.admin = admin;
    this.superuser = superuser;
    this.guest = guest;
}

public boolean isAdmin() {
    return admin;
}

public boolean isSuperuser() {
    return superuser;
}

public boolean isGuest() {
    return guest;
}

// and so on
}

Answer 6

多态性，而不是条件。

class User {
    final Print print;
    User(Print print) {
        this.print = print;
    }
}

interface Print {
    void print();
}

class CanPrint implements Print {
    public void print() { do whatever it takes to print a user }
}

class CannotPrint implements Print {
    public void print() { throw null; }
}

如何更好地表示用户权限？

6 个答案: