我有一个用Python编写的基本脚本来检查div并单击一个按钮。我使用browser.implicitly_wait
自动重新加载但是如何让它循环遍历代码而不重复它?
elem = browser.find_element_by_id('sitediv'); elem.send_keys('Red' + Keys.RETURN);
browser.implicitly_wait(10)
答案 0 :(得分:0)
你可以在互联网上找到有关python循环的文档。
以下是一个示例:
读得很好!
答案 1 :(得分:0)
这取决于你还在等什么。
这是一个示例,等待一个元素出现在具有while
和_is_visible
函数的页面上,以检查该元素是否存在于页面上:
class DockerContainerDeployer(object):
self.browser = webdriver.Firefox()
def deploy(self)
# actions...
# wait until the docker container is deployed
# by checking a div that give us the status
while not self._is_visible("#cluster-status .deployed"):
# you can add an implicity wait to check it every 10s with
# self.browser.implicitly_wait(10)
pass
# docker container deployed
def _is_visible(self, locator, timeout = 2):
"""
Check if an element is visible
"""
try:
ui.WebDriverWait(browser, timeout).until(EC.visibility_of_element_located((By.CSS_SELECTOR, locator)))
return True
except TimeoutException:
return False