Question

data example 我目前正试图解决问题。我有一个数据库，其表格为，id为co2_band，纳税年度，税率为。

我目前有这段代码

    SELECT tax_year, CO2_BAND AS band,
    CASE CO2_BAND = 116
    WHEN CO2_band BETWEEN 1 AND 116 THEN'116'
        WHEN CO2_band BETWEEN 95 AND 10 THEN 'fdjhgkjds'
    ELSE 'here'
    END AS b
    FROM company_car_tax
    WHERE tax_year LIKE '2015-16%'
    LIMIT 1

我的问题是在二氧化碳值50-75之间我必须四舍五入到最接近的记录怎么能这样做？

示例数据所以我有一个装满汽车的数据库和二氧化碳值。如果我有一辆车，它的二氧化碳值在50-75之间那么它需要选择75支架

Answer 1

SELECT tax_year, CO2_BAND AS band,
CASE  
WHEN CO2_band BETWEEN 1 AND 116 
  THEN'116'
WHEN CO2_band BETWEEN 95 AND 10 
  THEN 'fdjhgkjds'
WHEN CO2_band BETWEEN 50 AND 75
  THEN select max(CO2_band)  FROM company_car_tax where CO2_band BETWEEN 50 AND 75 group by tax_year
ELSE 'here'
END AS b
FROM company_car_tax
WHERE tax_year LIKE '2015-16%'
LIMIT 1

Answer 2

我建议您尝试下面显示的代码。请注意CASE条件的顺序很重要，因此我重新排列顺序以确保可以命中所有条件。我这样做是通过列出从限制最严格到限制最少的条件。但是，如果我自己这样做，我会指定条件，以便值中没有重叠。这将消除任何混淆。

SELECT tax_year, CO2_BAND as band,
       CASE WHEN CO2_band BETWEEN 50 AND 75 THEN '75'
            WHEN CO2_band BETWEEN 10 AND 95 THEN 'fdjhgkjds'
            WHEN CO2_band BETWEEN 1 AND 116 THEN '116'
            ELSE 'here' END AS b
FROM company_car_tax
WHERE tax_year LIKE '2015-16%'
LIMIT 1

使用sql案例时出现问题

2 个答案: