Question

嘿，我对编程很新，做了一些c＃，但对Python来说是全新的。我已将我的覆盆子pi（python3）中的图像发送到我的笔记本电脑（c＃）。我可以把字节发送但我不能打开图像，当它被接收（重新创建）？：（

顺便说一下这是我在stackoverflow上的第一篇文章，希望你能帮帮我:)。

C＃代码（接收）：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Net;
using System.Net.Sockets;
using System.Text;
using System.Threading.Tasks;
using System.Drawing;
using System.IO;

namespace tmpRaspTcpServer
{
    class Program
    {
        static void Main(string[] args)
        {

            IPAddress localAdd = IPAddress.Parse("xxx.xxx.xxx.xxx");
            TcpListener listener = new TcpListener(IPAddress.Any, 8888);
            Console.WriteLine("Listen...");
            listener.Start();

            while (true)
            {

                TcpClient client = listener.AcceptTcpClient();

                NetworkStream nwStream = client.GetStream();
                byte[] buffer = new byte[client.ReceiveBufferSize];

                int bytesRead = nwStream.Read(buffer, 0, client.ReceiveBufferSize);

                string dataReceived = Encoding.ASCII.GetString(buffer, 0, bytesRead);
                Console.WriteLine("Reading bytes: " );

                FileStream fs = new FileStream("c:\\tmp\\file.jpg", FileMode.Create);

                TraditionalReceiveBinary(nwStream, fs);
            }
        } 

        private static void TraditionalReceiveBinary(NetworkStream nwstream, FileStream fs)
        {
            // read the file in chunks of 1KB
            byte[] buffer = new byte[1024];

            int bytesRead;
            while ((bytesRead = nwstream.Read(buffer, 0, buffer.Length)) > 0)
            {

                fs.Write(buffer, 0, bytesRead);

                Console.Write("."); // a dot for each kb
            }
            fs.Flush();

        }
    }
}

Python3代码（发送）：

import socket
HOST, PORT = "xxx.xxx.xxx.xxx", 8888

image = open('image.jpg', 'rb')
image_data = image.read()
image.close()

socketData = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
socketData.connect((HOST,PORT))

socketData.sendall(image_data)

我没有收到任何错误，当我发送图片时，c＃app在控制台中制作了点，但文件被损坏了＃34;或者某事:(

我尝试过不同的编码和标题 - 但没有运气。

Answer 1

您正在丢弃正在从套接字读取的第一个TcpClient.ReceiveBufferSize字节：

int bytesRead = nwStream.Read(buffer, 0, client.ReceiveBufferSize);

这会破坏您的输出文件。

无法打开jpg（通过套接字从Python3发送到C＃）？

1 个答案: