Question

所以我得到了错误：

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\All Connected\profile.php on line 117

在尝试检查朋友请求状态信息时，我看到有人使用MySQL错误转储修复此问题或类似但我不确定，我可以获得一些帮助吗？

这是我的代码的片段，只有需要修复的部分

    mysql_connect("illuzionz-pc", "-----", "----------");
    mysql_select_db("allcon");

    $my_id = $_SESSION['user_id'];
    $profile_id = $_GET['id'];

    $check_friend_query = mysql_query("SELECT id FROM friends WHERE (user_one='$my_id' AND user_two='$profile_id') OR (user_one='$profile_id' AND user_two='$my_id')");

    if(mysql_num_rows($check_friend_query) == 1){
      echo "<br><a class='pure-button pure-button-disabled' href='#'>Already Friends!</a><br>";
      echo "<a class='button-error pure-button' href='#'>Unfriend {$user['first_name']}</a>";
    } else {
      mysql_connect("illuzionz-pc", "Admin", "0A562B0CA0");
      mysql_select_db("allcon");

      $my_id = $_SESSION['user_id'];
      $profile_id = $_GET['id'];

      $from_query = mysql_query("SELECT `id` FROM `friend_req` WHERE `from`='$profile_id' AND `to`='$my_id'");
      $to_query = mysql_query("SELECT `id` FROM `friend_req` WHERE `from`='$my_id' AND `to='$profile_id'");

      if(mysql_num_rows($from_query) == 1){
        echo "<a class='button-secondary pure-button' href='#'>Ignore Friend Request</a><br>";
        echo "<a class='button-success pure-button' href='#'>Accept Friend Request</a>";
      } else if(mysql_num_rows($to_query) == 1){
        echo "<a class='button-error pure-button' href='#'>Cancel Friend Request</a>";
      } else {
        echo "<a class='pure-button pure-button-primary' href='#'>Send Friend Request</a>"; 
      }
}

Answer 1

您的Option Strict On已经返回mysql_query，因为您传递了无效的SQL。将$ to_query修复为：

false

MySQL Numrows期待参数

1 个答案: