我的下拉菜单无法正常工作。 Here 你可以找到我正在处理的菜单。
当我按下' Produkte'应该打开一个包含2个子菜单点的下拉菜单。 如果我得到这个下拉列表,并且这些菜单点再次有子菜单,则应该有另一个下拉列表。这可能吗 ?如果是,那么,我对TypoScript来说是一个新手......
编辑:好吧,我刚看到<a href="#">..</a>
,我怎么能链接这个亲戚,所以如果我添加一个新的子菜单点,它会自动显示在那里?
也许使用data-target="dropdown"
?
lib.field_topmenu = HMENU
lib.field_topmenu {
1 = TMENU
1 {
wrap = <ul class="nav navbar-nav">|</ul>
expAll = 1
NO = 1
NO {
allWrap = <li>|</li>
ATagTitle.field = title
}
ACT = 1
ACT {
wrapItemAndSub = <li class="active">|</li>
ATagTitle.field = title
}
IFSUB = 1
IFSUB {
before = <a href="#" class="dropdown-toggle" data-toggle="dropdown" data-target="dropdown">
after = <b class="caret"></b></a>
doNotLinkIt = 1
wrapItemAndSub = <li class="dropdown">|</li>
ATagTitle.field = title
ATagParams = class="dropdown-toggle" data-toggle="dropdown"
ATagBeforeWrap = 1
}
ACTIFSUB = 1
ACTIFSUB {
before = <a href="#" class="dropdown-toggle" data-toggle="dropdown">
after = <b class="caret"></b></a>
# doNotLinkIt = 1
wrapItemAndSub = <li class="dropdown active">|</li>
ATagTitle.field = title
ATagBeforeWrap = 1
}
}
2 = TMENU
2 {
expAll = 1
wrap = <ul class="dropdown-menu">|</ul>
ACT = 1
ACT {
wrapItemAndSub = <li class="active">|</li>
ATagTitle.field = title
}
ACTIFSUB = 1
ACTIFSUB {
wrapItemAndSub = |
before = <li class="divider"></li><li class="nav-header">
after = </li>
# doNotLinkIt = 1
ATagTitle.field = title
}
NO {
allWrap = <li>|</li>
ATagTitle.field = title
}
IFSUB = 1
IFSUB {
before = <li class="divider"></li><li class="nav-header">
after = </li>
doNotLinkIt = 1
ATagTitle.field = title
}
SPC = 1
SPC {
allWrap = <li class="divider"></li><li class="nav-header">|</li>
}
}
3 = TMENU
3 {
NO {
allWrap = <li>|</li>
ATagTitle.field = title
}
ACT = 1
ACT {
wrapItemAndSub = <li class="active">|</li>
ATagTitle.field = title
}
}
答案 0 :(得分:2)
解决了问题。
lib.field_topmenu = HMENU
lib.field_topmenu {
entryLevel = 0
1 = TMENU
1 {
expAll = 1
wrap = <ul class="nav navbar-nav"> | </ul>
noBlur = 1
NO = 1
NO {
wrapItemAndSub = <li>|</li>
stdWrap.htmlSpecialChars = 1
ATagTitle.field = title
}
ACT <.NO
ACT {
wrapItemAndSub = <li class="active">|</li>
}
IFSUB <.NO
IFSUB {
allWrap = <!!==:>|
wrapItemAndSub = <li class="dropdown">|</li>
ATagBeforeWrap = 1
linkWrap = | <b class="caret"></b>
ATagParams = class="dropdown-toggle" data-toggle="dropdown"
}
ACTIFSUB < .IFSUB
ACTIFSUB {
allWrap = <!!==:>|
}
}
2 = TMENU
2 {
wrap = <ul class="dropdown-menu" role="menu" aria-labelledby="dLable">|</ul>
expAll = 1
NO = 1
NO {
allWrap = <li>|</li>
stdWrap.htmlSpecialChars = 1
}
ACT < .NO
ACT.ATagParams = class="active"
ACT.allWrap = <li class="active">|</li>
IFSUB < .NO
IFSUB.wrapItemAndSub = <li class="dropdown">|</li>
IFSUB.ATagParams = class="dropdown-toggle" data-toggle="dropdown"
IFSUB.linkWrap = | <b class="caret"></b>
IFSUB.ATagBeforeWrap = 1
ACTIFSUB < .IFSUB
ACTIFSUB {
allWrap = <!!==:>|
}
3 = TMENU
3 {
wrap = <ul class="dropdown-menu" role="menu" aria-labelledby="dLable">|</ul>
expAll = 1
NO = 1
NO.allWrap = <li>|</li>
NO.stdWrap.htmlSpecialChars = 1
ACT < .NO
ACT.ATagParams = class="active"
ACT.allWrap = <li class="active">|</li>
}
}
}
lib.title_banner = IMAGE
lib.title_banner {
file {
import.data = levelmedia:-1, slide
treatIdAsReference = 1
import.listNum = 0
}
}
答案 1 :(得分:0)
如果您希望整个子菜单中包含wrapItemAndSub
标记,则必须使用allWrap
代替<li>
。
通常,您应首先创建一个可用的HTML标记,然后使用TypoScript生成该标记。