Question

我需要加入3个表并显示所有数据：

以下查询正常。在这里，我加入了两个名为＆＃34; comparitive_statement1＆＃34;和＆＃34; comparitive_st_sup＆＃34;。一切都很好。

SELECT tc.*,sum(tci.total_inr) as tot1, tci.supplier_name,tci.currency as currency2 FROM comparitive_statement1 tc INNER JOIN comparitive_st_sup tci ON tc.tender_id=tci.tender_id WHERE tc.tender_id='$tender_id' and tc.sup_name=tci.supplier_name GROUP BY tc.sup_name ORDER BY tc.sup_name ASC

现在我需要再加一个名为＆＃34; comparitive_st_tech_compliance＆＃34;使用相同的tender_id和supplier_name。在这里，当我加入我的总数是错误的。放置我已完成的查询：

SELECT tc.*, sum(tci.total_inr) as tot1, tci.supplier_name,tci.currency as currency2 FROM comparitive_statement1 tc INNER JOIN comparitive_st_sup tci ON tc.tender_id=tci.tender_id INNER JOIN comparitive_st_tech_compliance cl ON tci.tender_id=cl.tender_id and tc.sup_name=cl.supplier_name WHERE tc.tender_id='$tender_id'  GROUP BY tc.sup_name,cl.supplier_name ORDER BY tc.sup_name ASC

我做错了什么？

Answer 1

可以是and tc.sup_name=cl.supplier_name部分

尝试

   INNER JOIN comparitive_st_tech_compliance cl ON 
   tci.tender_id=cl.tender_id and tc1.supplier_name=cl.supplier_name

在mysql / php问题中加入3个表

1 个答案: