Question

我试图从两个数组获得常见值，但是不敏感的匹配。但是不能成功。谓词是错误的。

    NSMutableArray *tempArray1 = [NSMutableArray arrayWithObjects:@"apple", @"cat", nil];
    NSMutableArray *tempArray2 = [NSMutableArray arrayWithObjects:@"APPLE", @"CAT", nil];
   // NSPredicate *resultPredicate1 = [NSPredicate predicateWithFormat:@"SELF IN [cd] %@", tempArray1];
    NSPredicate *resultPredicate1 = [NSPredicate predicateWithFormat:@"SELF [cd] IN  %@", tempArray1];
    NSMutableArray *arr_filteredtest = [NSMutableArray arrayWithArray:[tempArray2 filteredArrayUsingPredicate:resultPredicate1]];
    NSLog(@"%lu",(unsigned long)arr_filteredtest.count);

Answer 1

如果您需要两个数组中不区分大小写的唯一集，首先必须小写或大写所有字符串，然后创建NSSet：

NSMutableArray *joindArr = [NSArray arrayWithArray:tempArray1, nil];
[joindArr addObjectsFromArray:tempArray2];
NSMutableArray *arr1 = [[NSMutableArray alloc]init]; //make a nsmutableArray 
for (int i = 0; i<[arr count]; i++) {
    [arr1 addObject:[[arr objectAtIndex:i]lowercaseString]];
}
NSSet *set = [NSSet setWithArray:(NSArray*)arr1];//this set has unique values

Answer 2

您可以使用NSSet实现交叉，遗憾的是，使用NSSet的搜索区分大小写。

1.将两个数组转换为普通大小写，upperCase或lowerCase

2.使用intersectSet获取结果

示例：

NSMutableArray *tempArray1 = [NSMutableArray arrayWithObjects:@"apple", @"cat", nil]; NSMutableArray *tempArray2 = [NSMutableArray arrayWithObjects:@"APPLE", @"CAT", nil]; tempArray2 = [self convertStringObjectsToLoweCase:tempArray2]; //convert all elements to lower case/ upper case NSSet *set1 = [NSSet setWithArray:tempArray1]; NSSet *set2 = [NSSet setWithArray:tempArray2]; NSMutableSet *mutableSet = [NSMutableSet setWithSet:set1]; //Initialize with parent array,usually array with more elements [mutableSet intersectSet:set2]; NSArray *arrayContainingCommonObjects = [mutableSet allObjects]; NSLog(@"arrayContainingCommonObjects : %@",arrayContainingCommonObjects);

使用以下帮助方法

- (NSMutableArray *)convertStringObjectsToLoweCase:(NSMutableArray *)inputArray { [inputArray enumerateObjectsUsingBlock:^(id _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) { if ([obj isKindOfClass:[NSString class]]) { NSString *loweCaseString = [(NSString *)obj lowercaseString]; [inputArray replaceObjectAtIndex:idx withObject:loweCaseString]; } }]; return inputArray; }

<强>输出：

arrayContainingCommonObjects :( 苹果，猫）

Answer 3

我认为你应该尝试这个

    NSMutableArray *tempArray1 = [NSMutableArray arrayWithObjects:@"apple", @"cat", nil];
    NSMutableArray *tempArray2 = [NSMutableArray arrayWithObjects:@"apple", @"CAT", nil];
    NSMutableSet *intersection = [NSMutableSet setWithArray:tempArray1];
    [intersection intersectSet:[NSSet setWithArray:tempArray2]];
    NSArray *NEW_ARR = [intersection allObjects];
    NSLog(@"new arry::  %@",NEW_ARR);

谓词不敏感搜索两个字符串数组

3 个答案: