发布请求未从iOS设备到达服务器

时间:2015-11-27 03:33:01

标签: php ios objective-c nsurlsession

尝试向远程PHP文件发出简单的post请求。我没有收到服务器上的参数。我使用邮差Btw收到的。所以服务似乎没问题。这里似乎缺少iOS代码。

- (void) sendPostRequest {
NSError *error;

NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:baseURLPost];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"application/json" forHTTPHeaderField:@"Accept"];

[request setHTTPMethod:@"POST"];
NSDictionary *mapData = [[NSDictionary alloc] initWithObjectsAndKeys:
                         @"JSON", @"responseType",
                         [UserManager sharedInstance].user.username, @"username",
                            self.textView.text, @"text",
                         nil];

NSData *postData = [NSJSONSerialization dataWithJSONObject:mapData options:0 error:&error];
allowLossyConversion:YES];
[request setHTTPBody:postData];
[[session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
    if (error) {
        NSLog(@"%@", [error.userInfo valueForKey:@"NSDebugDescription"]);
    } else {
       NSArray *jsonResponseArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
        NSLog(@"%@", jsonResponseArray);
    }
}] resume];
}

我的PHP代码接收后REquest。

<?php
header("Content-type:application/json");

$postText= $_POST['text'];
$username = $_POST['username'];
$itemType = $_POST['itemType'];
$responseType = $_POST['responseType'];
$pictureLink = $_POST['pictureLink'];
$timestamp = $_POST['timestamp'];
$tags = $_POST['tags'];

if($timestamp==null){
    $timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>

jsonResponseArrayusername = "<null>";

3 个答案:

答案 0 :(得分:2)

使用

$handle = fopen('php://input','r'); 
$jsonInput = fgets($handle); 

而不是$_POST

像这样:

<?php
    header("Content-type:application/json");

$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$arr = json_decode($jsonInput, true);

$postText= $arr['text'];
$username = $arr['username'];
$itemType = $arr['itemType'];
$responseType = $arr['responseType'];
$pictureLink = $arr['pictureLink'];
$timestamp = $arr['timestamp'];
$tags = $arr['tags'];

if($timestamp==null){
    $timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>

答案 1 :(得分:1)

我终于在Swift中重新编写了整个iOS类,然后又重新开始了。 PHP服务已经存在了一段时间,过去一直对我很好。

答案 2 :(得分:0)

不正确的回答,但这段代码对我有用:

//Dict -> your dictionary, url -> the url for the action

NSData *data = [NSJSONSerialization dataWithJSONObject:dict 
                                               options:0
                                                 error:&error];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];

NSString *postLength=[NSString stringWithFormat:@"%lu",(unsigned long)[data length]];

[request setHTTPMethod:@"POST"];

[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setTimeoutInterval:20.0];
[request setHTTPBody:data];

//....
//rest of the code