尝试向远程PHP文件发出简单的post请求。我没有收到服务器上的参数。我使用邮差Btw收到的。所以服务似乎没问题。这里似乎缺少iOS代码。
- (void) sendPostRequest {
NSError *error;
NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:baseURLPost];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setHTTPMethod:@"POST"];
NSDictionary *mapData = [[NSDictionary alloc] initWithObjectsAndKeys:
@"JSON", @"responseType",
[UserManager sharedInstance].user.username, @"username",
self.textView.text, @"text",
nil];
NSData *postData = [NSJSONSerialization dataWithJSONObject:mapData options:0 error:&error];
allowLossyConversion:YES];
[request setHTTPBody:postData];
[[session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
if (error) {
NSLog(@"%@", [error.userInfo valueForKey:@"NSDebugDescription"]);
} else {
NSArray *jsonResponseArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
NSLog(@"%@", jsonResponseArray);
}
}] resume];
}
我的PHP代码接收后REquest。
<?php
header("Content-type:application/json");
$postText= $_POST['text'];
$username = $_POST['username'];
$itemType = $_POST['itemType'];
$responseType = $_POST['responseType'];
$pictureLink = $_POST['pictureLink'];
$timestamp = $_POST['timestamp'];
$tags = $_POST['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
此jsonResponseArray
为username = "<null>";
答案 0 :(得分:2)
使用
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
而不是$_POST
像这样:
<?php
header("Content-type:application/json");
$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$arr = json_decode($jsonInput, true);
$postText= $arr['text'];
$username = $arr['username'];
$itemType = $arr['itemType'];
$responseType = $arr['responseType'];
$pictureLink = $arr['pictureLink'];
$timestamp = $arr['timestamp'];
$tags = $arr['tags'];
if($timestamp==null){
$timestamp = date('Y-m-d G:i:s');
}
$arr = array('username' => $username);
echo json_encode($arr);
?>
答案 1 :(得分:1)
我终于在Swift中重新编写了整个iOS类,然后又重新开始了。 PHP服务已经存在了一段时间,过去一直对我很好。
答案 2 :(得分:0)
不正确的回答,但这段代码对我有用:
//Dict -> your dictionary, url -> the url for the action
NSData *data = [NSJSONSerialization dataWithJSONObject:dict
options:0
error:&error];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];
NSString *postLength=[NSString stringWithFormat:@"%lu",(unsigned long)[data length]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setTimeoutInterval:20.0];
[request setHTTPBody:data];
//....
//rest of the code